PHY201
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
5kg * 9.8m/s/s = 49N
6kg * 9.8 m/s/s = 58.8N
58.8N - 49N = 9.8N
If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
I AM NOT SURE OF HOW TO SET THIS PROBLEM UP. I BELIEVE THAT THE SPEED SHOULD BE SLOWING DOWN AND THE DIRECTION IN THE OPPOSITE DIRECTION.
During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
THE VELOCITY AND ACCELERATION ARE IN OPPOSITE DIRECTIONS AND THE SYSTEM SLOWS DOWN
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15MINS
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You have the right ideas. You need to declare a positive direction. See notes in the link below.
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#