Open Query 24

#$&*

course Mth 151

1/29 5

If your solution to stated problem does not match the given solution, you should self-critique per instructions at

http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm

Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

004. `Query 4

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Question: `q2.4.13 (formerly 2.4.12) This was not assigned but you answered similar questions and should be able to answer this one: n(A') = 25, n(B) = 28, n(A' U B') = 40, n(A ^ B) = 10. What is n(A - B)?

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Your solution:

We know the diagram as a whole equals to be 40. Since 10 of the elements included in B’s region are in the intersection then we know B contains 18. Since we know that everything outside of A should equal 25 we can determine that the area outside of the regions A and B can equal 7 since 25-18=7. Now that we have all these numbers plugged in we can determine that in order to reach 40 elements total we must subtract what we have from 40, so 40-25= 15. So the number for A is 15

confidence rating #$&*: 3

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Given Solution:

`a** In terms of the picture (2 circles, linked, representing the two sets) there are 28 in B and 10 in A ^ B so there are 18 in the region of B outside of A--this is the region B-A.

There are 25 outside of A, and 18 of these are accounted for in this region of B. Everything else outside of A must therefore also be outside of B, so there are 25-18=7 elements in the region outside of both A and B.

A ' U B ' consists of everything that is either outside of A or outside of B, or both. The only region that's not part of A ' U B ' is therefore the intersection A ^ B, since everything in this region is inside both sets.

A' U B' is therefore everything but the region A ^ B which is common to both A and B. This includes the 18 elements in B that aren't in A and the 7 outside both A and B. This leaves 40 - 18 - 7 = 15 in the region of A that doesn't include any of B. This region is the region A - B you are looking for.

Thus n(A - B) = 40 - 18 - 7 = 15.**

Supplementary comments:

For example, with (A' U B'), you ask the following questions in order:

What regions are in A?

What regions are therefore in A'?

What regions are in B?

What regions are therefore in B'?

So, what regions are in A' U B'?

If you can break a question down to a series of simpler questions, you can figure out just about anything.

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Self-critique (if necessary): I wasn’t sure at first if the question was asking if I should find the difference of A and B or if I just needed to fill in missing information. I’ll admit I peeked in order to see if I was in the right direction.

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Self-critique Rating:

@&

It's OK to peek, as long as you show your original reasoning and acknowledge having peeked.

*@

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Question: `qquery 2.4.19 wrote and produced 3, wrote 5, produced 7 &&&& How many did he write but not produce?

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Your solution:

He wrote 2 that he did not produce

We can come to that by subtracting the number that he did produce as well as write from the number of songs written total so 5-3=2

confidence rating #$&*:3

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Given Solution:

`a** You need to count the two he wrote and produced among those he wrote, and also among those he produced.

He only wrote 5, three of which he also produced. So he wrote only 2 without producing them.

In terms of the circles you might have a set A with 5 elements (representing what he wrote), B with 7 elements (representing what he produced) and A ^ B with 3 elements. This leaves 2 elements in the single region A - B and 5 elements in the single region B - A. The 2 elements in B - A would be the answer to the question. **

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Self-critique (if necessary):OK

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Self-critique Rating:

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Question: `q2.4.25 (formerly 2.4.24) 9 fat red r, 18 thn brown r, 2 fat red h, 6 thin red r, 26 fat r, 5 thin red h, 37 fat, 7 thin brown hens. ......!!!!!!!!...................................

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Your solution:

This question is not anywhere in the textbook that I could find. Both questions 24 and 25 are talking about religion, not thin brown hens. And since this is not worded as a question, I have no idea what I’m supposed to be figuring out.

@&

I'll have to check this against the current edition of the text.

*@

confidence rating #$&*:

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Given Solution:

`a** Here's my solution. Tell me if there is anything you disagree with (I'm not infallible) or don't understand.

incidental: 18 thin brown roosters, 7 thin brown hens, 6 thin red hens and the 6 thin roosters which aren't fat (out of the 50-26=24 thin roosters 18 are brown so 6 are red) adds up to 37 thin chickens

How many chickens are fat?

37 as given

How many chickens are red?

22: 9 fat red roosters, 6 thin red roosters, 5 thin red hens, 2 fat red hens.

How many chickens are male?

50: 9 fat red roosters are counted among the 26 fat roosters so the remaining 17 fat roosters are brown; then there are 18 thin brown roosters and 6 thin red roosters; the number of roosters therefore adds up to 9 + 18 + 6 + 17 = 50

How many chickens are fat not male?

26 of the 37 fat chickens are male, leaving 11 female

How many chickens are brown not fat?

25: 18 thin brown roosters, 7 thin brown hens adds up to 25 thin brown chickens

How many chickens are red and fat?

11: 9 fat red roosters and 2 fat red hens.**

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Self-critique (if necessary):

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Self-critique rating:

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Question: `q2.4.25 (formerly 2.4.24) 9 fat red r, 18 thn brown r, 2 fat red h, 6 thin red r, 26 fat r, 5 thin red h, 37 fat, 7 thin brown hens. ......!!!!!!!!...................................

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Your solution:

This question is not anywhere in the textbook that I could find. Both questions 24 and 25 are talking about religion, not thin brown hens. And since this is not worded as a question, I have no idea what I’m supposed to be figuring out.

@&

I'll have to check this against the current edition of the text.

*@

confidence rating #$&*:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

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Given Solution:

`a** Here's my solution. Tell me if there is anything you disagree with (I'm not infallible) or don't understand.

incidental: 18 thin brown roosters, 7 thin brown hens, 6 thin red hens and the 6 thin roosters which aren't fat (out of the 50-26=24 thin roosters 18 are brown so 6 are red) adds up to 37 thin chickens

How many chickens are fat?

37 as given

How many chickens are red?

22: 9 fat red roosters, 6 thin red roosters, 5 thin red hens, 2 fat red hens.

How many chickens are male?

50: 9 fat red roosters are counted among the 26 fat roosters so the remaining 17 fat roosters are brown; then there are 18 thin brown roosters and 6 thin red roosters; the number of roosters therefore adds up to 9 + 18 + 6 + 17 = 50

How many chickens are fat not male?

26 of the 37 fat chickens are male, leaving 11 female

How many chickens are brown not fat?

25: 18 thin brown roosters, 7 thin brown hens adds up to 25 thin brown chickens

How many chickens are red and fat?

11: 9 fat red roosters and 2 fat red hens.**

"

Self-critique (if necessary):

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Self-critique rating:

#*&!

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Question: `q2.4.25 (formerly 2.4.24) 9 fat red r, 18 thn brown r, 2 fat red h, 6 thin red r, 26 fat r, 5 thin red h, 37 fat, 7 thin brown hens. ......!!!!!!!!...................................

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Your solution:

This question is not anywhere in the textbook that I could find. Both questions 24 and 25 are talking about religion, not thin brown hens. And since this is not worded as a question, I have no idea what I’m supposed to be figuring out.

@&

I'll have to check this against the current edition of the text.

*@

confidence rating #$&*:

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

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Given Solution:

`a** Here's my solution. Tell me if there is anything you disagree with (I'm not infallible) or don't understand.

incidental: 18 thin brown roosters, 7 thin brown hens, 6 thin red hens and the 6 thin roosters which aren't fat (out of the 50-26=24 thin roosters 18 are brown so 6 are red) adds up to 37 thin chickens

How many chickens are fat?

37 as given

How many chickens are red?

22: 9 fat red roosters, 6 thin red roosters, 5 thin red hens, 2 fat red hens.

How many chickens are male?

50: 9 fat red roosters are counted among the 26 fat roosters so the remaining 17 fat roosters are brown; then there are 18 thin brown roosters and 6 thin red roosters; the number of roosters therefore adds up to 9 + 18 + 6 + 17 = 50

How many chickens are fat not male?

26 of the 37 fat chickens are male, leaving 11 female

How many chickens are brown not fat?

25: 18 thin brown roosters, 7 thin brown hens adds up to 25 thin brown chickens

How many chickens are red and fat?

11: 9 fat red roosters and 2 fat red hens.**

"

Self-critique (if necessary):

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Self-critique rating:

#*&!#*&!

&#Good work. See my notes and let me know if you have questions. &#