cq_1_051

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Phy 121

Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

** CQ_1_05.1_labelMessages **

The problem:

A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.

What will be its velocity after the 3 seconds has elapsed?

answer/question/discussion: ->->->->->->->->->->->-> scussion:

the ball is increasing in velocity 8cm/s every seconds. It it does this for 3 seconds it will have increased its velocity 24 cm/s. 8cm/s/s * 3 seconds = 24 cm/s. Since the starting velocity is 12cm/s, the velocity after 3 seconds will be 12cm/s + 24 cm/s which is 36cm/s

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Assuming that acceleration is constant, what will be its average velocity during this interval?

answer/question/discussion: ->->->->->->->->->->->-> scussion:

The avereage velocity is (v0+ vf)/2 = (12cm/s + 36cm/s) /2 = (48 cm/s )/ 2 = 24 cm/s

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How far will it travel during this interval?

answer/question/discussion: ->->->->->->->->->->->-> scussion:

If we multiply the average velocity by the time interval we will get the displacement.

`ds = vAve * `dt = 24 cm/s * 3 s = 72 cm

The ball travels 72 cm in during this interval.

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&#Very good responses. Let me know if you have questions. &#