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Phy 121
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_07.2_labelMessages **
An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
We need to calculate change in acceleration / change in slope
First roll has vAVE of 10m/8s = 1.25m/s
vf and `dv = 2*1.25 m/s = 2.5m/s
a = 2.5m/s/8s = .31 m/s/s
For second roll
vAVE of 10m/5s = 2m/s
vf and `dv = 2*2 m/s = 4m/s
a = 4m/s/5s = .8m/s/s
Delta a/Delta slope =( .8m/s/s - .31m/s/s) /( .10 - .05) =( .49m/s/s)/.05 = 9.8m/s/s
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