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course Phy 121
This is a resubmission. I originally submitted this sometime before 9/22. I haven't seen this posted, so I am resubmitting to ensure that you get it.Thanks for your patience.
9/25 9 pm" "A projectile leaves the edge of a table and, while traveling horizontally at a constant 15 cm/s, falls freely a distance of 133 cm to the floor. If its vertical acceleration is 980 cm/s2, how long does it take to fall and how far does it travel in the horizontal direction during the fall?
For the vertical fall we know v0, which is zero, `ds which is 133cm and a which is 980cm/s^2
Use the equation vf^2= v0^2 + 2a*`ds
vf^2 = 0 + 2*980cm/s^2 *133cm = 260,680cm^2/s2
Take square root of both sides
vf = 511cm/s (approx)
vAVe = (0 + 511cm/s)/2 = 256cm/s (approx)
vAve= `ds/dt
`dt= `ds/vAVe= 133cm/256 cm/s = .52s (approx)
It takes .52 seconds to fall
As for the horizontal distance, traveling at 15cm/s for .52 seconds, the projectile would travel approx 7.8cm
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&#This looks very good. Let me know if you have any questions. &#