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Phy 121
Your 'cq_1_10.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A pendulum requires 2 seconds to complete a cycle, which consists of a complete back-and-forth oscillation (extreme point to equilibrium to opposite extreme point back to equilibrium and finally to the original extreme point). As long as the amplitude of the motion (the amplitude is the distance from the equilibrium position to the extreme point) is small compared to the length of the pendulum, the time required for a cycle is independent of the amplitude.
· How long does it take to get from one extreme point to the other, how long from an extreme point to equilibrium, and how long to go from extreme point to equilibrium to opposite extreme point and back to equilibrium?
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answer/question/discussion: ->->->->->->->->->->->-> :
It takes 1 second to get from one extreme point to the other.
It takes .5 seconds to get from an extreme point to equilibrium.
It takes 1.5 seconds to get from an extreme point to equilibrium to opposite extreme point and back to equilibrium.
· What reasonable assumption did you make to arrive at your answers?
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answer/question/discussion: ->->->->->->->->->->->-> :
I assumed that the velocity was constant.
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The velocity actually isn't constant. The pendulum speeds up as it moves from extreme to equilibrium, and slows form equilibrium to extreme point. Even its average speed changes as the amplitude of the swings decreases.
The assumption implicit in your answers is that time from equilibrium to extreme is unchanging, and is equal to the time from extreme to equilibrium. This assumption is correct to a high degree of precision, as long as the amplitude of the swing is less than about 1/8 the length of the pendulum.
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About 7 minutes
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&#Good responses. See my notes and let me know if you have questions. &#