Week 5 Quiz2v2

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course Phy121

9/28 2:45pm

If the slope of a graph of the acceleration of a cart vs. the number of paper clips attached by a string and suspended over a pulley is ( 18 cm/s2) / clip, and if the slope of a graph of number of paper clips needed to maintain equilibrium vs. ramp slope is 59 clips / unit of ramp slope, then how many cm/s2 of acceleration should correspond to 1 unit of ramp slope? If 57 clips are necessary to match the mass of the cart, then if we could apply this force to the cart without the extra mass of all those clips, what would be the acceleration of the cart?This is a challenge.

If there are 59clips for unit of ramp slope, and 18cm/s^2 per clip then we would have

59clips/unit of ramp slope * 18cm/s^2/clip = 1062cm/s^2 per unit of ramp slope

If the mass of the cart is equal to 57clips and we applied this corresponding force to the cart we would have…

Fnet = m *a = 57 * 18cm/s^2 = 1026clips*cm/s^2

I feel there should be more to this, like actually calculating the mass or calculating the ramp slope, but I’m stumped as to taking this further.

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You've got it.

Of course this can and will be taken further in subsequent work.

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