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Phy 121
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_11.1_labelMessages **
Answer the following based on Newton's Second Law:
How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
Fnet = 12kg *3m/s^2 = 36kg*m/s^2 = 36Newtons
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What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
a = Fnet/m = 20kg*m/s^2/4kg = 5m/s^2
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If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2, then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
a= Fnet/m = 20kg*m/s^2/10kg = 2m/s^2
If it only accelerates 1.5 it means the net force is less than 2m/s^2, so other forces must be acting on the object opposite the direction of your force.
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What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
These forces have an acceleration of -.5m/s^2
F = m*a = 10kg*-.05m/s^2 = -5kg*m/s^2 = -5N These forces act in the opposite direction of your force.
&#Your work looks very good. Let me know if you have any questions. &#