open qa 11

course MTH 163

10/31/09 1:50 a.m.

If your solution to stated problem does not match the given solution, you should self-critique per instructions at

http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm

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Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

011.

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Question: `q001. Note that this assignment has 11 questions

How many squares one foot on a side would it take to construct a square two feet on a side?

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Your solution:

It will take 4 squares to make a square 2' x 2'

confidence rating: 3

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Given Solution:

A common response is that it takes 2 one-ft. squares to make a 2-foot square. However, below thought shows that this isn't the case. If we put 2 one foot squares side by side we get a one-foot by two-foot rectangle, not a square. If we put a second such rectangle together with the first, so that we have 2 rows with 2 squares in a row, then we have a two-foot square.

Thus we see that it takes 4 squares one foot on a side to make a square 2 ft. on a side.

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Question: `q002. How many cubes one foot on a side would it take to construct a cube two feet on a side?

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Your solution:

It would take 8 cubes to make the sides 2' and still have the cube shape

confidence rating: 3

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Given Solution:

We could begin by constructing two rows with two cubes in a row, which would sit on a square two feet by two feet. However this would not give is a cube two feet on a side, because at this point the figure we have constructed is only one foot high.

So we have to add a second layer, consisting of two more rows with two cubes a row.

Thus we have 2 layers, each containing 2 rows with 2 cubes in a row. Each layer has 4 cubes, so our two layers contain 8 cubes.

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Question: `q003. How many squares one foot on a side would it take to construct a square three feet on a side?

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Your solution:

It would take 9 squares

confidence rating:3

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Given Solution:

We would require three rows, each with 3 squares, for a total of 9 squares.

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Question: `q004. How many cubes one foot on a side would take to construct a cube three feet on a side?

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Your solution:

It would take 27 cubes

confidence rating:

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Given Solution:

This would require three layers to make a cube three feet high. Each layer would have to contain 3 rows each with three cubes. Each layer would contain 9 cubes, so the three-layer construction would contain 27 cubes.

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Question: `q005. Suppose one of the Egyptian pyramids had been constructed of cubical stones. Suppose also that this pyramid had a weight of 100 million tons. If a larger pyramid was built as an exact replica, using cubical stones made of the same material but having twice the dimensions of those used in the original pyramid, then what would be the weight of the larger pyramid?

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Your solution:

cubical stones = 100 million tons

It would take 8 of those cubical stones to make the pyramid twice the dimension

So the pyramid would be 8 * 100 = 800 million tons

confidence rating: 2

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Given Solution:

Each stone of the larger pyramid has double the dimensions of each stone of the smaller pyramid. Since it takes 8 smaller cubes to construct a cube with twice the dimensions, each stone of the larger pyramid is equivalent to eight stones of the smaller. Thus the larger pyramid has 8 times the weight of the smaller. Its weight is therefore 8 * 100 million tons = 800 million tons.

STUDENT QUESTION

I totally missed the mark on this one. Where did the 8 cubes come from (how is that calculated?)? I think that’s what is throwing me off.

INSTRUCTOR RESPONSE

If each pyramid is divided into the same number of cubes, in a geometrically similar manner, then the cubes of the second pyramid will have double the dimensions of the cubes making up the first.

If you double the dimensions of a cube, the larger cube could be built from 2 * 2 * 2 = 8 of the smaller, as you saw on a previous question.

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Question: `q006. Suppose that we wished to paint the outsides of the two pyramids described in the preceding problem. How many times as much paint would it take to paint the larger pyramid?

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Your solution:

It would take four times as much paint because we are dealing with the flat sides of the cubes or the squares and the second pyramid has 4 times the dimensions of the first pyramid

confidence rating: 2

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Given Solution:

The outside of each pyramid consists of square faces of uniform cubes. Since the cubes of the second pyramid have twice the dimension of the first, their square faces have 4 times the area of the cubes that make up the first. There is therefore 4 times the area to paint, and the second cube would require 4 times the paint

STUDENT COMMENT:

I’m not getting this concept at all.

INSTRUCTOR RESPONSE:

Normally I ask for more detail in a self-critique so I can tell what you do and do not understand, and give you the answer you need to see.

However in this case you have been doing well to this point, and self-critiquing when necessary, so I have a basis on which to focus my answer:

If the surface of each pyramid is divided into the same number of squares, in a geometrically similar manner, then the squares of the second pyramid will have double the dimensions of the squares making up the first.

If you double the dimensions of a square, the larger square could be built from 2 * 2 = 4 of the smaller.

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Question: `q007. Suppose that we know that y = k x^2 and that y = 12 when x = 2. What is the value of k?

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Your solution:

12= K(2)^2

12=4k

12/4 = K

K= 3

confidence rating: 4

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Given Solution:

To find the value of k we substitute y = 12 and x = 2 into the form y = k x^2. We obtain

12 = k * 2^2, which we simplify to give us

12 = 4 * k. The dividing both sides by 410 reversing the sides we easily obtain

k = 3.

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Question: `q008. Substitute the value of k you obtained in the last problem into the form y = k x^2. What equation do you get relating x and y?

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Your solution:

y= 3(x)^2

x^2=y/3

x = +/- sqrt(y/3)

confidence rating: 3

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Given Solution:

We obtained k = 3. Substituting this into the form y = k x^2 we have the equation y = 3 x^2.

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Question: `q009. Using the equation y = 3 x^2, determine the value of y if it is known that x = 5.

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Your solution:

y= 3 (5)^2

y= 3(25)

y= 75

confidence rating: 4

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Given Solution:

If x = 5, then the equation y = 3 x^2 give us y = 3 (5)^2 = 3 * 25 = 75.

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Question: `q010. If it is known that y = k x^3 and that when x = 4, y = 256, then what value of y will correspond to x = 9? To determine your answer, first determine the value of k and substitute this value into y = k x^3 to obtain an equation for y in terms of x. Then substitute the new value of x.

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Your solution:

256 = k(4)^3

256 = K(64)

256/64 = k

k = 4

y= 4(9)^3

y = 4(729)

y= 2916

confidence rating: 4

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Given Solution:

To we first substitute x = 4, y = 256 into the form y = k x^3. We obtain the equation

256 = k * 4^3, or

256 = 64 k. Dividing both sides by 64 we obtain

k = 256 / 64 = 4.

Substituting k = 4 into the form y = k x^3, we obtain the equation y = 4 x^3.

We wish to find the value of y when x = 9. We easily do so by substituting x equal space 9 into our new equation. Our result is

y = 4 * 9^3 = 4 * 729 = 2916.

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Question: `q011. If it is known that y = k x^-2 and that when x = 5, y = 250, then what value of y will correspond to x = 12?

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Your solution:

250 = K(5)^-2

250 = k(1/25)

250 = k(.04)

6250 = k

y= 6250 (12)^-2

y= 6250 ( 1/144)

y= 6250(.006944)

y ~ 43.4028

confidence rating:3

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Given Solution:

Substituting x = 5 and y = 250 into the form y = k x^-2 we obtain

250 = k * 5^-2. Since 5^-2 = 1 / 5^2 = 1/25, this becomes

250 = 1/25 * k, so that

k = 250 * 25 = 6250.

Thus our form y = k x^-2 becomes y = 6250 x^-2.

When x = 12, we therefore have

y = 6250 * 12^-2 = 6250 / 12^2 = 6250 / 144 = 42.6, approximately.

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&#This looks very good. Let me know if you have any questions. &#