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PHY 241
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
The problem:
A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds.
The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
What is the clock time at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
midpoint = [(x_1 +x_2)/2,(y_1+y_2)/2]
= (9, 28)
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What is the velocity at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
28 cm/s
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How far do you think the object travels during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
28 cm/s * 8 s = 224 cm
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By how much does the clock time change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
delta(s) = 13 s - 5 s = 8 s
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By how much does velocity change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
delta(v) = 40 cm/s - 16 cm/s = 24 cm/s
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What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
delta(v_avg) = delta(v) / delta(s)
= 3 cm/s^2
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What is the rise of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
y_2 - y_1 = 40 - 16 = +24
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What is the run of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
x_2 - x_1 = 13 -5 = +8
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What is the slope of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
slope = rise/run = 3
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What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
the slope of the graph v(t) is equal to acceleration
if the graph was distance vs time, the slope would be velocity
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What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
delta(v_avg) = delta(v) / delta(s)
= 3 cm/s^2
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*#&!
&#This looks very good. Let me know if you have any questions. &#
#$&*
PHY 241
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
The problem:
A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds.
The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
What is the clock time at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
midpoint = [(x_1 +x_2)/2,(y_1+y_2)/2]
= (9, 28)
#$&*
What is the velocity at the midpoint of this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
28 cm/s
#$&*
How far do you think the object travels during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
28 cm/s * 8 s = 224 cm
#$&*
By how much does the clock time change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
delta(s) = 13 s - 5 s = 8 s
#$&*
By how much does velocity change during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
delta(v) = 40 cm/s - 16 cm/s = 24 cm/s
#$&*
What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
delta(v_avg) = delta(v) / delta(s)
= 3 cm/s^2
#$&*
What is the rise of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
y_2 - y_1 = 40 - 16 = +24
#$&*
What is the run of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
x_2 - x_1 = 13 -5 = +8
#$&*
What is the slope of the graph between these points?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
slope = rise/run = 3
#$&*
What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
the slope of the graph v(t) is equal to acceleration
if the graph was distance vs time, the slope would be velocity
#$&*
What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
delta(v_avg) = delta(v) / delta(s)
= 3 cm/s^2
#$&*
*#&!
&#This looks very good. Let me know if you have any questions. &#