cq_1_031

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PHY 241

Your 'cq_1_03.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.

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v_avg = delta(s)/delta(t)

= (30 - 0)/ (5 - 0) = 6 cm/s

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If the acceleration of the ball is uniform then its average velocity is equal to the average of its initial and final velocities.

You know its average velocity, and you know the initial velocity is zero.

What therefore must be the final velocity?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

v_1 = 0

v_avg = 6 cm/s

v_final = 12 cm/s

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By how much did its velocity therefore change?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

delta(v) = 12 cm/s

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At what average rate did its velocity change with respect to clock time?

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

delta(v)/t = 12/5 cm/s^2

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What would a graph of its velocity vs. clock time look like? Give the best description you can.

answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):

constant acceleration would mean its a linear equation that starts at (0,0) with a slope of 12/5

y= 12/5x

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&#Very good responses. Let me know if you have questions. &#