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PHY 241
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
v_ave = 'ds/'dt
= 2 m/ .64 s
= 3.125 m/s
v_0 = 0
v_f = 6.25 m/s
'ds= 2 m
'dt = .64 s
vf = v0 + a * `dt
a = (v_f - v_0) / 'dt
= 6.25 m/s / .64 s
= 9.8 m/s^s
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Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
v_ave = 'ds/'dt
= 5 m/ 1.05 s
= 4.76 m/s
v_0 = 0
v_f = 9.52 m/s
'ds = 5m
'dt = 1.05 s
a = (v_f - v_0) / 'dt
= 9.52 m/s / 1.05 s
= 9.1 m/s^2
The percent difference betweent the two solutions is 7%, so to say they are consistent, more balls would have to be dropped from a high place to really show consistency.
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&#Very good responses. Let me know if you have questions. &#