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course PHY 241
830pm 10/24/2011
Determine the acceleration of an object whose velocity is initially 24 cm/s and which accelerates uniformly through a distance of 66 cm in 3.8 seconds.
v_0 = 24 cm/s
'ds = 66 cm
'dt = 3.8 s
`ds = (v0 + vf) / 2 * `dt
v_f = 2*'ds/'dt - v_0
= 132cm/ 3.8s - 24 cm/s
= 34.7 - 24 cm/s
= 10.7 cm/s
a = 'dv/'dt
= (10.7 cm/s - 24 cm/s) / 3.8 seconds
= -3.5 cm/s^2"
&#Your work looks very good. Let me know if you have any questions. &#