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course PHY 241
340pm 10/27/2011
A projectile leaves the edge of a table and, while traveling horizontally at a constant 37 cm/s, falls freely a distance of 149 cm to the floor. If its vertical acceleration is 980 cm/s2, how long does it take to fall and how far does it travel in the horizontal direction during the fall?
y-component
a = 980 cm/s^2 in the positive downward direction
'ds = 149 cm
v_0 = 0
'ds = v_0 * 'dt + (a/2) * 'dt^2
149 cm = 0 + (980 cm/s^2 / 2) * 'dt^2
'dt = +-sqrt(0.152 s^2)
= +- 0.3899 s and since time is not negative in this case it's simply 0.39 s
x-component
a= 0
v_0 = 37 cm/s
'ds = v_0 * 'dt + (a/2) * 'dt^2
= 37 cm/s * 0.39 s + 0
= 14.4 cm
This looks very good. Let me know if you have any questions.