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Phy 241
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Masses of 5 kg and 6 kg are suspended from opposite sides of a light frictionless pulley and are released.
What will be the net force on the 2-mass system and what will be the magnitude and direction of its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
F_a=m*a
= 6kg*9.81m/s^2
= 58.86 N
F_b=m*a
= 49.05 N
F_net = 9.81N
F_net = m*a
a= F_net/m
= 9.81N/11kg
= 0.89 m/s^2
Direction: -y direction
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If you give the system a push so that at the instant of release the 5 kg object is descending at 1.8 meters / second, what will be the speed and direction of
motion of the 5 kg mass 1 second later?
answer/question/discussion: ->->->->->->->->->->->-> :
3.6 m/s in the -y direction
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Velocity is changing at rate .89 m/s^2. It won't change by 3.6 m/s in 1 second. The downward speed of the 5 kg object won't increase.
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During the first second, are the velocity and acceleration of the system in the same direction or in opposite directions, and does the system slow down or speed up?
answer/question/discussion: ->->->->->->->->->->->-> :
Velocity and acceleration are in the same direction.
The system speeds up at a constant acceleration
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