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Phy 241
Your 'cq_1_11.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Answer the following based on Newton's Second Law:
How much net force is required to accelerate a 12 kg mass at 3 m/s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
Fnet = m * a
= (3 m/s^2) / 12 kg
= 36 N
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What would be the acceleration of a 4 kg mass subject to a net force of 20 Newtons?
answer/question/discussion: ->->->->->->->->->->->-> :
Fnet = m*a
a = Fnet/m
= 20 N / 4 kg
= 5 m/s^2
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If you exert a force of 20 Newtons on a 10-kg object and it accelerates in the direction of your force at 1.5 m/s^2,
then how do you know there are other forces acting on the object besides your own?
answer/question/discussion: ->->->->->->->->->->->-> :
F = m * a
20 N = 10 kg * 1.5 m/s^2
20 N /= 15 N
There is another force of 5 N acting against your force
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What is the total of all those forces and in what direction does this total act?
answer/question/discussion: ->->->->->->->->->->->-> :
5 N acting in the opposite direction of your force. So if your force is positive, 5 N is negative
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&#Very good responses. Let me know if you have questions. &#