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Phy 241
Your 'cq_1_19.3' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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An object moving in the direction 120 degrees (as measured counterclockwise to the positive x axis) encounters a net force whose direction is 270 degrees.
Sketch the force and its component along the line of motion, as well as its component perpendicular to the line of motion.
answer/question/discussion: ->->->->->->->->->->->-> :
I sketched a vector positioned at 120 degrees counter clockwise from the positive x-axis.
I also scketed a vector that runs along the negative y-axis.
The component of the force along the line of motion is opposite of the line of motion, which is positioned at 300° counterclockwise from the positive x-axis
The component perpendicular to the line of motion is 90° from 300° and 120°, or halfway between those two angles
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Suppose you are facing in the direction of motion. Do you perceive the component of the force along the line of motion to be forward or backward?
It this component in the direction of motion or opposite to the direction of motion?
answer/question/discussion: ->->->->->->->->->->->-> :
backward, opposite the direction of motion
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Will the object speed up, slow down or maintain a constant speed?
answer/question/discussion: ->->->->->->->->->->->-> :
slow down
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If you are facing in the direction of motion, then the line perpendicular to the direction of motion will run to your right and to your left.
Is the component of the force perpendicular to the line of motion directed to the right or to the left?
answer/question/discussion: ->->->->->->->->->->->-> :
to your left
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Will the object veer to the right, to the left or maintain straight-line motion?
answer/question/discussion: ->->->->->->->->->->->-> :
veer to the left
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Which is greater in magnitude, the component of the force along the line of motion or the component perpendicular to the line of motion?
answer/question/discussion: ->->->->->->->->->->->-> :
120° + 270° = 390° or 30° which is 90 degrees from the line of motion
120° + 90° = 210° which is 80 degrees from the line of motion. So therefore the component of the force along the line of motion is greater.
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&#Very good responses. Let me know if you have questions. &#