#$&*
Phy 121
Your 'cq_1_05.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
For every second of time that elapses, the ball accelerates by 8 cm/s. This means that after one second it will have a velocity of 20 cm/s, after two 28 cm/s, and after three 36 cm/s. So after 3 seconds, the ball will have a velocity of 36 cm/s.
#$&*
• Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
To find the average velocity, you find the average of the beginning velocity and the ending velocity.
38+12= 50
50/2
You should include units with your quantities, but it seems clear that you have averaged initial and final velocity, the correct thing to do.
Note that the final velocity is 48 cm/s, not 38 cm/2.
The average velocity is 25 cm/s.
#$&*
• How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
Distance= rate x time
25 cm/s * 3
75 cm
#$&*
** **
15 min
** **
No need to submit a revision unless you have questions; you had one arithmetic error but no errors in procedure. However be sure you are using units at every step. Check the discussion at the link below.
&#See any notes I might have inserted into your document. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified.If your solution is completely consistent with the given solution, you need do nothing further with this problem. &#