#$&*
Phy 121
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
The acceleration increases from 0.315 m/s^2 to 0.8 m/s^2 when you increase the slope from .05 to 0.1. This means the average change in acceleration is (0.3125 m/s^2 + 0.8 m/s^2) / 2 =0.556 m/s^2
10 m
.05 slope
8 seconds
1.25 m/s average velocity
2.5 final velocity
2.5 / 8 = .3125 m/s2
10 m
.1 incline
5 second
2 m/s average velocity
4 m/s final velocity
4 / 5 = .8 m/s2
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30 minutes
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Good work on the accelerations.
That last rate of change question is seldom interpreted correctly on the first try. Do submit a revision on that part.
&#See any notes I might have inserted into your document. If there are no notes, this does not mean that your solution is completely correct.
Then please compare your solutions with the expanded discussion at the link
Solution
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