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Phy 121
Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_02.1_labelMessages.txt **
The problem:
A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.
• What is your best guess about the ball's average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Without completing the calculations, I can just guess that the average velocity will be some number between 4 cm/sec(low) and 10 cm/sec(high). I would say that it would be somewhere around 7 cm/sec, since that is about between those two numbers.
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• Without further information, why is this just a guess?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): This is just a guess because I have not done any of the calculations to find the exact average. I just guessed based on knowing the definition of an average.
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• If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): I would guess that the ball traveled about 21 cm, based off my earlier aver velocity of 7 cm/sec. I then just multiplied 7 cm/sec by the 3 seconds it took to get from position one to the second.
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• At what average rate did its velocity change with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line): Based on the earlier guesses the average rate of chain of velocity with respect to clock time= (change in velocity)/(change in clock time)
6 cm/sec (fro problem 1: 10cm/sec-4cm/sec=6cm/sec) and multiply that by 2 seconds (change in clock time: 2 sec) to get 3 cm/sec^2
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20 minutes
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&#Very good responses. Let me know if you have questions. &#