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phy 121
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** CQ_1_07.2_labelMessages **
An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
• At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
1st trial:
vAve=10m/8m
=1.25 m/sec
v_0 is 0 m/s
v_f=2.5 m/s (1.25 m/s*2)
a = (( 2.5 m/s - 0 m/s ) / 8 s )
= .3125 m^2
2nd Trial:
vAve = 10 meters/5 seconds
= 2 m/ second
v_0= 0 m/s
v_f= 4 m/s (2 m/sec*2)
a = (( 4 m/s - 0 m/s ) / 5 s )
= .8 m/s^2
Acceleration to Slope:
( .8 m/s^2 - .3125 m/s^2) / ( .10 - .05 ) = 9.75 m/s^2
9.75 m/s^2-average rate of the automobile's acceleration changing with respect to the slope of the incline
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20 min
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&#Very good responses. Let me know if you have questions. &#