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Phy 121
Your 'cq_1_19.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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Asst 19 Question 1
The equilibrant of a force is the force which is equal and opposite to that force. If two forces are equal and opposite, their x and y components are also equal, but the x and y components of the force are opposite in sign to those of the equilibrant.
The x and y components of a force are 2 Newtons and 3 Newtons repectively.
• What are the magnitude of this force and what angle does it make as measured counterclockwise from the positive x axis? #$&*
• 2N^2+3N^2=F^2
⁃ F=3.6 N
• Angle: arctan(3N/2N)= 56 degrees
• What are the components of the equilibrant force? #$&*
• comp are equal and pop to the components of the force
• xcomp: -2N
• ycomp:-3N
• What angle does the equilibrant force make as measured counterclockwise from the positive x axis? #$&*
• arctan(-3N/-2N)+180 deg=56 degrees+180 deg= 236 deg
⁃ ??why cant we just add 360 degrees at once, since 180+180 totals to 360 and they both are negative components.
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The equilibrant will be at 180 degrees, as you have found using the rules.
I don't think you would want to add 360 degrees, which would just take you around to the same vector you started with.
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