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Phy 121
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** CQ_1_19.2_labelMessages **
Asst 19 Question 2
Sketch a vector representing a 10 Newton force which acts vertically downward.
• Position an x-y coordinate plane so that the initial point of your vector is at the origin, and the angle of the vector as measured counterclockwise from the positive x axis is 250 degrees. This will require that you 'rotate' the x-y coordinate plane from its traditional horizontal-vertical orientation.
answer/question/discussion: ->->->->->->->->->->->-> :
x axis- 20 degrees above horizontal, y-axis 20 degrees to vertical left direction. Negative y axis (since it is to the left of the origin) rotates 20 degrees as well.
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• What are the x and y components of the equilibrant of the force?
answer/question/discussion: ->->->->->->->->->->->-> :
First find the x/y comp with magnitude of 10 N, at 250 degrees
xcomp: 10N*cos(250deg)=-3N
ycomp: 10N*sin(250 deg)=-9N
Since this is the equilibrate of the force the components are equal and opposite:
xcom=+3N and ycomp=+9N
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&#Very good responses. Let me know if you have questions. &#