assgn3qa1

course mth 173

003.

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Question: `qNote that there are four questions in this assignment.

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Question: `q001. Sketch a graph similar to that you constructed for the stock values, this time for the depth of the water vs. clock time (depths 80, 40, 20 at clock times

10, 40, 90). Your first point, for example, will be (10, 80). Connect these points with straight lines and determine the slopes of the lines.

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Your solution: The first two points, (10,80) and (40,40), gives a rise of -40 and a run of 30, after dividing -40 by 30 you get -1.3. The next set, (40,40) and (90,20),

gives you a rise of -20 and a run of 50, when divided this gives -.4

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Given Solution:

`aThe three points are (10, 80), (40, 40) and (90, 20).

From the first point to the second the rise is from 80 to 40, or -40, and the run is from 10 to 40, or 30. So the slope is -40 / 30 = -1.33.

From the second point to the third the rise is from 40 to 20, or -20, and the run is from 40 to 90, or 50, so the slope is -20 / 50 = -.4. Click on 'Next Picture' to see

graph.

`routine graph3

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Question: `q002. Look at your results for the slopes, and look the results for the average rates of change. What do you notice? In what way then does the graph represent

the average rate of change?

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Your solution:The slopes and rates of change are the same. The rise is the same thing as change in water level and the run is time taken.

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Given Solution:

`aThe slopes and the rates of change are numerically equal. For example between the second and third points the rise of -20 represents the -20 cm change in depth and the run

of 50 represents the 50 seconds required to make this change, so the slope represents the -20 cm / (50 sec) average rate of change over the second time interval. We therefore

see that slope represents average rate of change.

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Question: `q003. To what extent do you think your graph with three points and straight line segments between them accurately depicts the detailed behavior of the water over

the 80-second period of observation?

How do you think the actual behavior of the system differs from that of the graph?

How do you think the graph of the actual behavior of the system would differ from that of the graph you made?

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Your solution: It does not accurately depict the detailed behavior, in an exact graph it would be curved instead of straight lines.

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Given Solution:

`aThe straight line segments would indicate a constant rate of change of depth. It is fairly clear that as depth decreases, the rate of change of depth will decrease, so that

the rate of change of depth will not be constant. The graph will therefore never be straight, but will be a curve which is decreasing at a decreasing rate.

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Question: `q004. From the given information, do you think you can accurately infer the detailed behavior of the water depth over the 80-second period? Do you think you can

infer the detailed behavior better than you could the values of the stocks? Why or why not?

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Your solution: No you can't accurately tell the detailed behavior over an 80 second period. It will be more accurate than the stock value problem because the stock market is

unpredictable, where as we know the water has to flow out.

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Given Solution:

`aIt will turn out that three data points will be sufficient to infer the detailed behavior, provided the data are accurate. However you might or might not be aware of that

at this point, so you could draw either conclusion. However it should be clear that the behavior of the water depth is much more predictable than the behavior of the stock

market. We don't know on a given day whether the market will go up or down, but we do know that if we shoot a hole in the bottom of a full bucket the water level will

decrease, and we expect that identical holes in identical buckets should result in the same depth vs. clock time behavior.

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&#This looks very good. Let me know if you have any questions. &#