course mth 173
4/20 1:00
The Celsius temperature of a hot potato placed in a room is given by the function T = 40* 2- .007 t + 24 , where t is clock time in seconds and T is temperature in Celsius.
At what average rate is the temperature of the potato changing between clock times t = 6.8 and t = 6.9 seconds seconds? -.1877368 C/s
At what average rate is the temperature of the potato changing between clock times t = 6.8 and t = 6.81 seconds? -.18778 C/s
At what average rate is the temperature of the potato changing between clock times t = 6.8 and t = 6.801 seconds? -.18779 C/s
Your results are good, but you should indicate at least briefly how you got them.
What do you estimate is the rate at which temperature is changing at clock time t = 6.8 seconds? -.188 C/s
The rate at which the Celsius temperature of a hot potato placed in a room is given by Rate = .041 * 2- .007 t, where R is rate of change in Celsius degrees per second and t is clock time in seconds. How much temperature change do you estimate would occur between t = 6.8 and t = 13.6 seconds?
By evaluating for the two times, t = 6.8 R = .039669327 C/s, t = 13.6 R = .038381841 C/s. Then after adding the two together and dividing by two I found the avg. rate over the interval to be .039025584 C/s, the interval was 6.8 seconds long, which you multiply the two to find .265373971 degrees C.
very well explained
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