phy 121
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The problem:
A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
If the ball is accelerating at 8 cm/s/s for 3 sec, that would be 8 * 3 = 24 cm/s change over the 3 seconds. Given the 12 cm/s initial velocity, 12 + 24 = 36 cm/s at the end
of the 3 second interval.
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Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
If acceleration is constant, given the laws of uniform acceleration the avg. velocity will be the avg between the final and initial velocities. 12 cm/s + 36 cm/s = 48 cm/s,
48 / 2 = 24 cm/s is the average velocity.
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How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
If the vAve = 24 cm/s and the interval is 3 seconds, 24 * 3 = 72 cm.
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30 minutes
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Very good responses. Let me know if you have questions.