Phy 201
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A ball is tossed vertically upward and caught at the position from which it was released.
Ignoring air resistance will the ball at the instant it reaches its original position be traveling faster, slower, or at the same speed as it was when released?
answer/question/discussion: ->->->->->->->->->->->-> :
#$&* Ignoring air resistance, the ball at the instant it reaches its original position will be traveling the same speed as it took off with. Gravity has the same distance to both work against and then with the ball. There are no other net forces or resistances effecting the ball, so the speed at which the ball left the hand will be the same speed at which it returns to that exact position.
What, if anything, is different in your answer if air resistance is present? Give your best explanation.
answer/question/discussion: ->->->->->->->->->->->-> :
#$&* If air resistance is thrown into the equation, the ball should return to the original position at a slower speed than it took off. The air resistance works as friction to the force as the ball descends, making the velocity less. However, I don't think the air resistance effects the ball as it ascends.
air resistance affects anything that moves at a nonzero velocity relative to the air
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About 10 minutes...
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Solution
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