Phy 201
Your 'cq_1_25.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A steel ball of mass 110 grams moves with a speed of 30 cm / second around a circle of radius 20 cm.
* What are the magnitude and direction of the centripetal acceleration of the ball?
answer/question/discussion: ->->->->->->->->->->->-> sion:
#$&* Using a = v^2 / r, I get the centripetal acceleration to be .30m/s ^2 * .20m = 0.45m/s^2. The direction of the acceleration should share the same direction as velocity, which is around the circle.
* What is the magnitude and direction of the centripetal force required to keep it moving around this circle?
answer/question/discussion: ->->->->->->->->->->->-> sion:
#$&* Using the acceleration I determined above, I plug that and the mass in F_cent = m * a = .11kg * .45m/s^2 = 0.0495 N, and this force is directed towards the center of the circle.
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about 10 minutes....
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&#This looks very good. Let me know if you have any questions. &#