Phy 201
Your 'cq_1_27.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball of mass 400 grams is immersed in water. The ball is suspended in the water by a rubber band chain which exerts a tension force of 2.5 Newtons on the ball.
* What is the weight of the ball?
answer/question/discussion: ->->->->->->->->->->->-> sion:
#$&* Weight of an object is the amount of force exerted by gravity. So the ball's weight = m * g = 0.4kg * 9.8m/s^2 = 3.92 Newtons
* What is the buoyant force on the ball?
answer/question/discussion: ->->->->->->->->->->->-> sion:
#$&* F_buoy = weight of the displaced water. And I recall from previous problems that the weight + F_buoy + T = 0. So I plug in the information and rearrange the equation to give me F_buoy = 3.92N + -2.5N = 1.42N.
* What therefore must be its volume?
answer/question/discussion: ->->->->->->->->->->->-> sion:
#$&* The mass of displaced water * acceleration due to gravity = F_buoy. So, m = 1.42N / 9.8m/s^2 = 0.145 kg. From here, I know Volume = m * 1g/cm^3 = 145g * 1g/cm^3 = 145cm^3.
* What is its density?
answer/question/discussion: ->->->->->->->->->->->-> sion:
#$&* The density is that of water, which is universally 1 g/cm^3.
That's the density of the water, not the ball.
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about 15 minutes
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Check the link to be sure you understand the density calculation. Submit a revision if you're not sure.
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#