Phy 201
Your 'cq_1_06.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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For each situation state which of the five quantities v0, vf, `ds, `dt, and ‘a’ are given, and give the value of each.
• A ball accelerates uniformly from 10 cm/s to 20 cm/s while traveling 45 cm.
answer/question/discussion: ->->->->->->->->->->->-> : I am a little confused by the wording here, but I think I am given the v0 = 10cm/s, vf = 20cm/s, and ‘ds = 45cm.
• A ball accelerates uniformly at 10 cm/s^2 for 3 seconds, and at the end of this interval is moving at 50 cm/s.
answer/question/discussion: ->->->->->->->->->->->-> : The acceleration is given as 10 cm/s^2, as well as the ‘dt = 3 seconds and vf = 50cm/s.
• A ball travels 30 cm along an incline, starting from rest, while accelerating at 20 cm/s^2.
answer/question/discussion: ->->->->->->->->->->->-> : Given in this problem are the ‘ds = 30cm, v0 = 0cm/s, and the ‘a’ = 20cm/s/s.
Then for each situation answer the following:
• Is it possible from this information to directly determine vAve?
answer/question/discussion: ->->->->->->->->->->->-> : In this first problem, yes. We are given v0 and vf, so (v0 + vf) / 2 = vAve. In the second problem, no. To get the vAve, we have to first determine the v0 and then we can use (v0 + vf) / 2 to get the vAve. And in the third problem, no. To find vAve here, we have to use the formula vf^2 = v0^2 + 2(a * ‘ds). From there we can use that vf to average it off with the v0 to determine the vAve.
• Is it possible to directly determine `dv?
answer/question/discussion: ->->->->->->->->->->->-> : In the first problem, yes. We simply subtract the v0 by the vf. In the second problem, yes. We just have to multiply the ‘dt by the ‘a’ to determine the ‘dv. In the third problem, no. We’d have to manipulate the problem a little bit and determine the ‘dt so we can use a = ‘dv / ’dt.
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About 30 minutes
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&#Your work looks very good. Let me know if you have any questions. &#