course Phy 121 i think i am getting it alittle better now ????????????assignment #002 002. Velocity Physics I 06-12-2008
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10:09:31 `q001. Note that there are 14 questions in this assignment. If an object moves 12 meters in 4 seconds, then at what average rate is the object moving? Explain how you obtained your result in terms of commonsense images.
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RESPONSE --> 3meters/sec you divide 12 by 4 confidence assessment: 3
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10:18:35 `q002. How is this problem related to the concept of a rate?
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RESPONSE --> rate is a ratio of time and measure which the 12 meters and 4 seconds confidence assessment: 2
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10:21:27 `q003. Is object position dependent on time or is time dependent on object position?
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RESPONSE --> the object position is dependent of time confidence assessment: 3
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10:21:41 Object position is dependent on time--the clock runs whether the object is moving or not so time is independent of position. Clock time is pretty much independent of anything else.
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RESPONSE --> got it self critique assessment: 3
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???? ????}Y?????assignment #002 002. Velocity Physics I 06-12-2008 ??W?????????????assignment #002 002. Velocity Physics I 06-12-2008
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14:00:53 `q001. Note that there are 14 questions in this assignment. If an object moves 12 meters in 4 seconds, then at what average rate is the object moving? Explain how you obtained your result in terms of commonsense images.
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RESPONSE --> confidence assessment:
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14:01:39 `q004. So the rate here is the average rate at which position is changing with respect to clock time. Explain what concepts, if any, you missed in your explanations.
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RESPONSE --> confidence assessment:
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14:02:02 You should always self-critique your work in this manner. Always critique your solutions by describing any insights you had or errors you makde, and by explaining how you can make use of the insight or how you now know how to avoid certain errors. Also pose for the instructor any question or questions that you have related to the problem or series of problems.
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RESPONSE --> ok sounds good self critique assessment: 1
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14:05:24 `q005. If an object is displaced -6 meters in three seconds, then what is the average speed of the object what is its average velocity? Explain how you obtained your result in terms of commonsense images and ideas.
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RESPONSE --> 2m/s because i divided 6 by 3 confidence assessment: 1
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14:05:51 Speed is the average rate at which distance changes, and distance cannot be negative. Therefore speed cannot be negative. Velocity is the average rate at which position changes, and position changes can be positive or negative.
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RESPONSE --> ok self critique assessment: 1
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14:09:36 `q007. How do you write the expressions `ds and `dt on your paper?
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RESPONSE --> i would right it as a triangle and a s confidence assessment: 3
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14:09:48 You use the Greek capital Delta symbol Delta. `d is often used here because the symbol for Delta is not interpreted correctly by some Internet browsers. You should get in the habit of thinking and writing Delta when you see `d. You may use either `d or Delta when submitting work and answering questions.
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RESPONSE --> ok self critique assessment: 3
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14:11:18 `q008. If an object changes position at an average rate of 5 meters/second for 10 seconds, then how far does it move? How is this problem related to the concept of a rate?
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RESPONSE --> 2m would be how far it moved. you are finding the rate of the object moving confidence assessment: 2
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14:13:21 In this problem you are given the rate at which position changes with respect to time, and you are given the time interval during which to calculate the change in position. Given the rate at which one quantity changes with respect to another, and the change in the second quantity, how do we obtain the resulting change in the first?
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RESPONSE --> i don't understand what it is asking for self critique assessment: 1
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14:15:30 To find the change in a quantity we multiply the rate by the time interval during which the change occurs. We therefore obtain the change in position by multiplying the velocity by the time interval: `ds = vAve * `dt. The units of this calculation pretty much tell us what to do: Just as when we multiply pay rate by time (dollar / hr * hours of work) or automobile velocity by the time interval (miles / hour * hour), when we multiply vAve, in cm / sec or meters / sec or whatever, by `dt in seconds, we get displacement in cm or meters, or whatever, depending on the units of distance used.
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RESPONSE --> ok i understand somewhat better now self critique assessment: 3
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14:19:34 `q010. Explain how the quantities average velocity vAve, time interval `dt and displacement `ds are related by the definition of a rate, and how this relationship can be used to solve the current problem problem.
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RESPONSE --> dt divided byr ds is rate and vave is the average confidence assessment: 2
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14:19:50 vAve is the average rate at which position changes. The change in position is the displacement `ds, the change in clock time is `dt, so vAve = `ds / `dt.
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RESPONSE --> ok self critique assessment: 2
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14:22:25 `q012. How is this result related to our intuition about the meanings of the terms average velocity, displacement and clock time?
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RESPONSE --> i don;t understand this part confidence assessment:
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14:30:56 `q013. What algebraic steps do we use to solve the equation vAve = `ds / `dt for `dt, and what is our result?
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RESPONSE --> muitply ds and vave confidence assessment: 1
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14:31:31 To solve vAve = `ds / `dt for `dt, we must get `dt out of the denominator. Thus we first multiply both sides by the denominator `dt. Then we can see where we are and takes the appropriate next that. The steps: vAve = `ds / `dt. Multiply both sides by `dt: vAve * `dt = `ds / `dt * `dt Since `dt / `dt = 1 vAve * `dt = `ds. We can now divide both sides by vAve to get `dt = `ds / vAve.
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RESPONSE --> i see how to do it been awhile since i had any math self critique assessment:
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