Phy231
Your 'cq_1_07.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
** **
An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
*
At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> scussion:
slope=rise/run='dt/'ds=.05 vAve1=10m/8s=1.25m/s a=2.5m/s /8s= .312m/s^2
vAve2=10m/5s=2m/s a=4m/s /5s= .8m/s^2
The acceleration more than doubles with the twice as steep incline.
#$&*
** **
5min
** **
3/3/10 11am
Your accelerations are correct, but you haven't yet calculated the specified average rate.
&#Please compare your solutions with the expanded discussion at the link
Solution
Self-critique your solutions, if this is necessary, according to the usual criteria. Insert any revisions, questions, etc. into a copy of this posted document. Mark any insertions with &&&& so they can be easily identified. &#