Assignment 3a qa

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course Math 173

9/13/2010 @ 10:31pm

If your solution to stated problem does not match the given solution, you should self-critique per instructions at

http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm

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Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

003.

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Question: `qNote that there are four questions in this assignment.

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Self-critique (if necessary):

ok

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Self-critique rating #$&*

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Question: `q001. Sketch a graph similar to that you constructed for the stock values, this time for the depth of the water vs. clock time (depths 80, 40, 20 at clock times 10, 40, 90). Your first point, for example, will be (10, 80). Connect these points with straight lines and determine the slopes of the lines.

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Your solution:

For the first line segment that connects coordinates (10,80) and (40,40) the slope of the segment is (40-80)/(40-10) = -40/30 = -4/3

For the second line segment with endpoints at (40,40) and (90, 20) the slope of the segment is (20-40)/(90-40) = -20/50 = -2/5

confidence rating #$&* 3

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Given Solution:

`aThe three points are (10, 80), (40, 40) and (90, 20).

From the first point to the second the rise is from 80 to 40, or -40, and the run is from 10 to 40, or 30. So the slope is -40 / 30 = -1.33.

From the second point to the third the rise is from 40 to 20, or -20, and the run is from 40 to 90, or 50, so the slope is -20 / 50 = -.4. Click on 'Next Picture' to see graph.

`routine graph3

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Self-critique (if necessary):

ok

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Self-critique rating #$&*

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Question: `q002. Look at your results for the slopes, and look the results for the average rates of change. What do you notice? In what way then does the graph represent the average rate of change?

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Your solution:

The slopes and the average rates of change are identical. The slope is equivalent to the average rate of change as represented on the graph.

confidence rating #$&* 3

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Given Solution:

`aThe slopes and the rates of change are numerically equal. For example between the second and third points the rise of -20 represents the -20 cm change in depth and the run of 50 represents the 50 seconds required to make this change, so the slope represents the -20 cm / (50 sec) average rate of change over the second time interval. We therefore see that slope represents average rate of change.

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Self-critique (if necessary):

ok

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Self-critique rating #$&*

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Question: `q003. To what extent do you think your graph with three points and straight line segments between them accurately depicts the detailed behavior of the water over the 80-second period of observation?

How do you think the actual behavior of the system differs from that of the graph?

How do you think the graph of the actual behavior of the system would differ from that of the graph you made?

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Your solution:

The graph does not accurately depict the exact behavior of the water over a time period. The actual behavior of the water is more of a curve with the steepest portion of the curve being in the lower times and a shallower curve occurs as the water empties toward zero.

confidence rating #$&* 3

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Given Solution:

`aThe straight line segments would indicate a constant rate of change of depth. It is fairly clear that as depth decreases, the rate of change of depth will decrease, so that the rate of change of depth will not be constant. The graph will therefore never be straight, but will be a curve which is decreasing at a decreasing rate.

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Self-critique (if necessary):

ok

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Self-critique rating #$&*

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Question: `q004. From the given information, do you think you can accurately infer the detailed behavior of the water depth over the 80-second period? Do you think you can infer the detailed behavior better than you could the values of the stocks? Why or why not?

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Your solution:

We cannot infer the detailed behavior of the water over the time frame just from the graph. We would require many more points to be plotted in order to see the actual behavior. We can determine the behavior better than we could for the stock market. The behavior of the water can be expected to be the same or close to the same regardless as to how many times the experiment is run. The stock market is influenced by many variables that change constsntly. Therefore it would be much more difficult if not impossible to accurately predict the behavior of the market in a detailed fashion.

confidence rating #$&* 3

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Given Solution:

`aIt will turn out that three data points will be sufficient to infer the detailed behavior, provided the data are accurate. However you might or might not be aware of that at this point, so you could draw either conclusion. However it should be clear that the behavior of the water depth is much more predictable than the behavior of the stock market. We don't know on a given day whether the market will go up or down, but we do know that if we shoot a hole in the bottom of a full bucket the water level will decrease, and we expect that identical holes in identical buckets should result in the same depth vs. clock time behavior.

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Self-critique (if necessary):

ok

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Self-critique rating #$&*

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&#Very good work. Let me know if you have questions. &#

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