Randomized Problem 3

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course Mth 173

1/30/11 9:43pm

The Celsius temperature of a hot potato placed in a room is given by the function T = 51* 2- .0094 t + 17 , where t is clock time in seconds and T is temperature in Celsius. •At what average rate is the temperature of the potato changing between clock times t = 7.5 and t = 7.6 seconds seconds?

The average rate of temperature change between t=7.5 and t=7.6 is -1.3 degrees/second.

• At what average rate is the temperature of the potato changing between clock times t = 7.5 and t = 7.51 seconds?

The average rate of temperature change between t=7.5 and t=7.51 is -10.5 degrees/second.

• At what average rate is the temperature of the potato changing between clock times t = 7.5 and t = 7.501 seconds?

The average rate of temperature change between t=7.5 and t=7.501 is -100 degrees/ second.

• What do you estimate is the rate at which temperature is changing at clock time t = 7.5 seconds?

I estimate the rate of change for temperature at t=7.5 seconds to be -1000 degrees/second.

The rate at which the Celsius temperature of a hot potato placed in a room is given by Rate = .039 * 2- .0094 t, where R is rate of change in Celsius degrees per second and t is clock time in seconds. How much temperature change do you estimate would occur between t = 7.5 and t = 15 seconds?

If T= 0.27855 for t=7.5 and T= 0.530535 for t=15, then 0.530535-0.27855 is the temperature change. Temperature change= 0.251985 degrees Celsius.

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@& You will need to redo this, and include the details of your calculations. Most of your answers are incorrect, and I believe you're leaving out a step, but I can't tell just from the answers what that step might be.

Please provide more explanation in your solutions, and resubmit.*@