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Phy 201
Your 'cq_1_02.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A ball starts with velocity 4 cm/sec and ends with a velocity of 10 cm/sec.
What is your best guess about the ball's average velocity?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
The balls average velocity would be increasing because the initial and end velocity increases.
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@& This question asks for a specific numerical response.*@
Without further information, why is this just a guess?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
Because we dont have the time differences to calculate average velocity.
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If it takes 3 seconds to get from the first velocity to the second, then what is your best guess about how far it traveled during that time?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
6 cm/sec because 10 cm/sec 4 cm/sec is 6 cm/sec
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@& The distance traveled isn't determined by the change in velocity.
You can go a long ways at 60 mph without speeding up or slowing down. If the change in velocity was what determined how far you go, you wouldn't get anywhere at that speed.
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At what average rate did its velocity change with respect to clock time during this interval?
answer/question/discussion: ->->->->->->->->->->->-> (start in the next line):
(6 cm/sec) / 3 sec = 2 cm/sec2
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@& Good, and your units are correct.
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*#&!
@& Good work on the last question, which is the one students most frequently miss..
However you'll need to insert a few responses on earlier questions and resubmit. See my notes.
Please mark your insertions with @@@@ so I can easily locate them.
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