#$&*
course Phy 121
A projectile leaves the edge of a table and, while traveling horizontally at a constant 22 cm/s, falls freely a distance of 104 cm to the floor. If its vertical acceleration is 980 cm/s2, how long does it take to fall and how far does it travel in the horizontal direction during the fall?I know:
horizontal vel = 22cm/s
`ds = 104cm
a = 980cm/s^2
v0 = 0m/s
I want:
`dt = how long it takes to fall
`ds(horizontal) = how far it travels in the horizontal direction = `dt * horizontal vel
`ds = v0`dt + .5(a)(`dt)^2
`ds = .5a(`dt)^2
`ds / .5a = (`dt)^2
104cm / 490cm/s^2 = `dt^2
104cm * 1s^2 / 490cm = `dt^2
.2s^2 = `dt^2
+-sqrt(.2s^2) = +-sqrt(`dt^2)
.4s = `dt
So with a horizontal velocity of 22cm/s over .4s the ball will move 8.8cm horizontally after it leaves the table. "
&#Very good responses. Let me know if you have questions. &#