course Phy 232

Problems 103,106,and 109 are answered on the previous section of problems I turned in. 111)

H=KA(Th-Tc/L)=A(Th-Tc)/R

H=0.8((0.15)(80-Tc)/0.15)

-0.12=12-0.15Tc

-12.12=-0.15Tc

Tc= 80.8

H=0.8(7.0(80-Tc)/0.15)

-0.12=560-7.0Tc

-560.12=-7.0Tc

Tc=80

Ratio being 1

114)

(A): Temp. gradient at cooler end is 140 degrees C. How mamy J of heat will flow across this end per second?

H=KA(Th-Tc/L)

=(380)(0.025)(0-140/120)

= 9.5(1.2)

= 11.4J

(B): H=KA(Th-Tc/L)

= 380(0.025)(100-0/120)

= 9.5(0.8)

= 7.6J

115)

(0.70)(600)=420J/s

330,000Jx12=3,960,000J which would equal 9,428.6 seconds

116)

(A): What is the rate of radiation of energy/unit area from suns surface?

=(4.28055x10^26/4pi(6.96x10^8)^2)

= 4.28055x10^26/4pi(4.84416x10^17)

= 4.28055x10^26/12.57(4.84416x10^17)

= 4.28055x10^26/6.089x10^18

= 7.03x10^7

(B): H=dQ/dt

= 4.28055x10^26

H=AeoT^4= 4pi(6.96x10^8)^2(1)(5.670400(4)x10^-8)T^4

=12(4.84416x10^17)(2.26816x10^-6)T^4

=5.812992x10^18(2.26816x10^-6)

=(1.318x10^13)^4

=3.02x10^52"