question

On the homework you assigned wed, I can't figure out how to find the area for these given newtons and length.

I know that the line is NOT straight (Does this change the way I would find the area or velocity?),

but to find avg vel. I would need to take (the change in distance )/ (the change in time),

I however, don't have the time, and the distance is in the place of where the time should be on the graph.

Do I just let the force in newtons stand for the change in time?

I tried finding the area, like you would with a straight line, I found it by (0+1.3)/2 Then I took my answer from this and multiplied by .65(9-8)=area, =.65

But still this method would only find the area of a rectangle of the space under the line.

It still wouldn't find the area of the triangle. I know its just an estimate of the area, but I'm not sure what to do.

Assuming that the x = 8 cm and x = 9 cm 'altitudes' are 0 and 1.3, which I believe is the case, you did this correctly.
What you effectively did was replace the slightly curving graph between the x = 8 and x = 9 points with a straight line, which as you can see stays very close to the graph. This results in a trapezoidal region under the graph.
The area of the trapezoid is equal to its average altitude multiplied by its width. The average altitude is (0 + 1.3 N) / 2 = .65 N, and the width is 9 cm - 8 cm = 1 cm, so the area represents .65 N * 1 cm = .65 N * cm.