Phys 201
Your 'cq_1_02.2' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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The problem:
A graph is constructed representing velocity vs. clock time for the interval between clock times t = 5 seconds and t = 13 seconds. The graph consists of a straight line from the point (5 sec, 16 cm/s) to the point (13 sec, 40 cm/s).
What is the clock time at the midpoint of this interval?
answer/question/discussion:
13s-5s=8s
What is the velocity at the midpoint of this interval?
answer/question/discussion:
40cm/s-16cm/s=24cm/s
How far do you think the object travels during this interval?
answer/question/discussion:
40cm
By how much does the clock time change during this interval?
answer/question/discussion:
13s-5s=8s
By how much does velocity change during this interval?
answer/question/discussion:
40cm/s-16cm/s=24cm/s
What is the average rate of change of velocity with respect to clock time on this interval?
answer/question/discussion:
(40cm/s)/(13s)=3.1cm
What is the rise of the graph between these points?
answer/question/discussion:
-4s
What is the run of the graph between these points?
answer/question/discussion:
7cm/s
What is the slope of the graph between these points?
answer/question/discussion:
(7cm/s)/(-4s)= 1.75 cm
What does the slope of the graph tell you about the motion of the object during this interval?
answer/question/discussion:
the object is speeding up
What is the average rate of change of the object's velocity with respect to clock time during this interval?
answer/question/discussion:
(40cm/s +16cm/s)/2=56/2=28 13s+5s=18s/2=9s
28/9= 3.11cm/s
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20min
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&#At least part of your solution does not agree with the solution and comments given at the link below. You should view the solution at that link and self-critique as indicated there.
Solution
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