Phy 201
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A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion:
dv= 8cm/s^2*3s
dv= 24cm/s
dv=vf-vo
vf= vd+vo
vf= dv+vo
= 24cm/s+12 cm/s
vf= 36cm/s
Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion:
vAve= ( vf+vo)/2
= (36cm/s+12cm/s)/2
= 24cm/s
How far will it travel during this interval?
answer/question/discussion:
ds= dv*t
=24cm/s*3s
= 72cm
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15 min
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&#Your work looks very good. Let me know if you have any questions. &#