Asst_29_QA

course PHY 201

ìè»Ô‡Ã©¡‡EÖ졇ӞàÎèEàóÑÈ’kwÐÊÑÀassignment #029

029. Radian measure of angle; angular position, angular velocity

Physics II

05-03-2008

......!!!!!!!!...................................

15:43:00

`q001. Note that this assignment contains 15 questions.

If an object moves a distance along the arc of a circle equal to the radius of the circle, it is said to move through one radian of angle. If a circle has a radius of 40 meters, then how far would you have to walk along the arc of the circle to move through one radian of angle? How far would you have to walk to move through 3 radians?

......!!!!!!!!...................................

RESPONSE -->

40 m, 120 m

confidence assessment: 2

.................................................

......!!!!!!!!...................................

15:43:08

Since 1 radian of angle corresponds to the distance along the arc which is equal to the radius, if the radius of the circle is 40 meters then a 1 radian angle would correspond to a distance of 40 meters along the arc.

An angle of 3 radians would correspond to a distance of 3 * 40 meters = 120 meters along the arc. Each radian corresponds to a distance of 40 meters along the arc.

......!!!!!!!!...................................

RESPONSE -->

self critique assessment: 3

.................................................

......!!!!!!!!...................................

15:45:44

`q002. On a circle of radius 40 meters, how far would you have to walk to go all the way around the circle, and through how many radians of angle would you therefore travel? Through how many radians would you travel if you walked halfway around the circle? Through how many radians would you travel if you walked a quarter of the way around the circle?

......!!!!!!!!...................................

RESPONSE -->

pi*80 m = 251.33 m

251.33 / 40 = 6.283 or 2pi radians

251.33 / 2 / 40 = 3.14 or pi radians

251.33 / 4 / 40 = 1.57 or pi/2 radians

confidence assessment: 2

.................................................

......!!!!!!!!...................................

15:46:18

The circumference of a circle is the product of `pi and its diameter, or in terms of the radius r, which is half the diameter, C = 2 `pi r. The circumference of this circle is therefore 2 `pi * 40 meters = 80 `pi meters.

This distance can be left in this form, which is exact, or if appropriate this distance can be approximated as 80 * 3.14 meters = 251 meters (approx).

The exact distance 2 `pi * 40 meters is 2 `pi times the radius of the circle, so it corresponds to 2 `pi radians of arc.

Half the arc of the circle would correspond to a distance of half the circumference, or to 1/2 ( 80 `pi meters) = 40 `pi meters. This is `pi times the radius so corresponds to `pi radians of angle.

A quarter of an arc would correspond to half the preceding angle, or `pi/2 radians.

......!!!!!!!!...................................

RESPONSE -->

self critique assessment: 3

.................................................

......!!!!!!!!...................................

15:56:57

`q003. On a circle of radius 6 meters, what distance along the arc would correspond to 3 radians? What distance would correspond to `pi / 6 radians? What distance would correspond to 4 `pi / 3 radians?

......!!!!!!!!...................................

RESPONSE -->

6 m * 3 = 18 m

`pi/6 radians = `pi*r/6 = `pi * 6/6 = `pi

4`pi/3 radians = 4`pi/3 * 6 = 24`pi/3 = 8`pi

confidence assessment: 2

.................................................

......!!!!!!!!...................................

15:57:07

3 radians along the arc would correspond to an arc distance of 3 times the radius, or 3 * 6 meters, or 18 meters.

`pi / 6 radians would correspond to `pi / 6 times the radius, or `pi / 6 * 6 meters = `pi meters.

4 `pi / 3 radians would correspond to 4 `pi / 3 * 6 meters = 8 `pi meters.

......!!!!!!!!...................................

RESPONSE -->

self critique assessment: 3

.................................................

......!!!!!!!!...................................

15:58:02

`q004. If you were traveling around a circle of radius 50 meters, and if you traveled through 4 radians in 8 seconds, then how fast would you have to be moving?

......!!!!!!!!...................................

RESPONSE -->

4 radians * 50 m = 200 m

200 m / 8 sec = 25 m/s

confidence assessment: 2

.................................................

......!!!!!!!!...................................

15:58:07

If you travel 4 radians along the arc you half traveled an arc distance of 4 times the radius, or 4 * 50 meters = 200 meters.

If you traveled this distance in 8 seconds your average speed would be 200 meters / (8 seconds) = 25 m/s.

......!!!!!!!!...................................

RESPONSE -->

self critique assessment: 3

.................................................

......!!!!!!!!...................................

15:58:45

`q005. Traveling at 3 radians / second around a circle of radius 20 meters, how fast would you have to be moving?

......!!!!!!!!...................................

RESPONSE -->

3 radians/sec * 20 m = 60 m/s

confidence assessment: 2

.................................................

......!!!!!!!!...................................

15:58:48

3 radians along the arc is a distance of 3 times the radius, or 3 * 20 meters = 60 meters. Moving at 3 radians/second, then, the speed along the arc must be 3 * 20 meters / sec = 60 meters /sec.

......!!!!!!!!...................................

RESPONSE -->

self critique assessment: 3

.................................................

......!!!!!!!!...................................

16:00:07

`q006. If you know how many radians an object travels along the arc of a circle, and if you know the radius of the circle, how do you find the distance traveled along the arc? Explain the entire reasoning process.

......!!!!!!!!...................................

RESPONSE -->

We know radians traveled and distance of a radian (ie radius of the circle) so we simply multiply the distance of 1 radian times number of radians.

confidence assessment: 2

.................................................

......!!!!!!!!...................................

16:00:15

The distance traveled along the arc of circle is 1 radius for every radian. Therefore we multiply the number of radians by the radius of the circle to get the arc distance.

......!!!!!!!!...................................

RESPONSE -->

self critique assessment: 3

.................................................

......!!!!!!!!...................................

16:00:42

`q007. If you know the distance an object travels along the arc of a circle, and if you know the radius of the circle, how do you find the corresponding number of radians?

......!!!!!!!!...................................

RESPONSE -->

Divide the distance traveled by the radius.

confidence assessment: 2

.................................................

......!!!!!!!!...................................

16:00:50

An arc distance which is equal to the radius corresponds to a radian. Therefore if we divide the arc distance by the radius we obtain the number of radians.

......!!!!!!!!...................................

RESPONSE -->

self critique assessment: 3

.................................................

......!!!!!!!!...................................

16:02:49

`q008. If you know the time required for an object to travel a given number of radians along the arc of a circle of known radius, then how do you find the average speed of the object?

......!!!!!!!!...................................

RESPONSE -->

Divide the number of radians by the time required which leaves you with the number of radians per time unit. Multply the number of radians by the radius to yield the units of distance per time unit.

confidence assessment: 2

.................................................

......!!!!!!!!...................................

16:02:58

If you know the number of radians you can multiply the number of radians by the radius to get the distance traveled along the arc. Dividing this distance traveled along the arc by the time required gives the average speed of the object traveling along the arc.

......!!!!!!!!...................................

RESPONSE -->

self critique assessment: 3

.................................................

......!!!!!!!!...................................

16:04:27

`q009. If you know the speed of an object along the arc of a circle and you know the radius of the circle, how do you find the angular speed of the object in radians/second?

......!!!!!!!!...................................

RESPONSE -->

Speed is in units of distance per units of time. By dividing the units of distance by the radius we find the number of radians per unit of time.

confidence assessment: 2

.................................................

......!!!!!!!!...................................

16:04:44

The speed of the object is the distance it travels along the arc per unit of time. The angular velocity is the number of radians through which the object travels per unit of time. The distance traveled and the number radians are related by the fact that the distance is equal to the number of radians multiplied by the radius. So if the distance traveled in a unit of time is divided by the radius, we get the number of radians in a unit of time. So the angular speed is found by dividing the speed along the arc by the radius.

......!!!!!!!!...................................

RESPONSE -->

self critique assessment: 3

.................................................

......!!!!!!!!...................................

16:08:45

`q010. We usually let `d`theta stand for the anglular displacement in radians between two points on the arc of the circle. We usually let `omega stand for the angular velocity in radians / second. We let `ds stand for the distance traveled along the arc of a circle, and we let r stand for the radius of the circle. If we know the radius r and the arc distance `ds, what is the anglular displacement `d`theta, in radians?

......!!!!!!!!...................................

RESPONSE -->

`ds / r = `d`theta

confidence assessment: 2

.................................................

......!!!!!!!!...................................

16:08:52

Since an angular displacement of 1 radian corresponds to an arc distance equal to the radius, the anglular displacement `theta in radians is equal to the number of radii in the arc distance `ds. This quantity is easily found by dividing the arc distance by the radius. Thus

`d`theta = `ds / r.

......!!!!!!!!...................................

RESPONSE -->

self critique assessment: 3

.................................................

......!!!!!!!!...................................

16:09:28

`q011. If we know the radius r of a circle and the angular velocity `omega, how do we find the velocity v of the object as it moves around the arc of the circle?

......!!!!!!!!...................................

RESPONSE -->

`omega * r = v

confidence assessment: 2

.................................................

......!!!!!!!!...................................

16:09:34

The angular velocity is the number of radians per second. The velocity is the distance traveled per second along the arc. Since an angular displacement of 1 radian corresponds to an arc distance equal to the radius, if we multiply the number of radians per second by the radius we get the distance traveled per second. Thus

v = `omega * r.

......!!!!!!!!...................................

RESPONSE -->

self critique assessment: 3

.................................................

......!!!!!!!!...................................

16:10:43

`q012. We can change an angle in degrees to radians, or vice versa, by recalling that a complete circle consists of 360 degrees or 2 `pi radians. A half-circle is 180 degrees or `pi radians, so 180 degrees = `pi radians. How many radians does it take to make 30 degrees, how many to make 45 degrees, and how many to make 60 degrees?

......!!!!!!!!...................................

RESPONSE -->

30 degrees = pi/6 radians

45 degrees = pi/4 radians

60 degrees = pi/3 radians

confidence assessment: 2

.................................................

......!!!!!!!!...................................

16:10:52

30 degrees is 1/6 of 180 degrees and therefore corresponds to 1/6 * `pi radians, usually written as `pi/6 radians.

45 degrees is 1/4 of 180 degrees and therefore corresponds to 1/4 * `pi radians, or `pi/4 radians.

60 degrees is 1/3 of 180 degrees and therefore corresponds to 1/3 * `pi radians, or `pi/3 radians.

......!!!!!!!!...................................

RESPONSE -->

self critique assessment: 3

.................................................

......!!!!!!!!...................................

16:13:44

`q013. Since 180 deg = `pi rad, we can convert an angle from degrees to radians or vice versa if we multiply the angle by either `pi rad / (180 deg) or by 180 deg / (`pi rad). Use this idea to formally convert 30 deg, 45 deg and 60 deg to radians.

......!!!!!!!!...................................

RESPONSE -->

30 deg * `pi rad/180 deg = 30 pi deg rad / 180 deg = pi rad / 6

45 deg * `pi rad/180 deg = 45 pi deg rad / 180 deg = pi rad / 4

60 deg * `pi rad/180 deg = 60 pi deg rad / 180 deg = pi rad / 3

confidence assessment: 2

.................................................

......!!!!!!!!...................................

16:13:56

To convert 30 degrees to radians, we multiply by the rad / deg conversion factor, obtaining

30 deg * ( `pi rad / 180 deg) = (30 deg / (180 deg) ) * `pi rad = 1/6 * `pi rad = pi/6 rad.

To convert 45 degrees to radians we use the same strategy:

{}45 deg * (`pi rad / 180 deg) = ( 45 deg / ( 180 deg) ) * `pi rad = 1/4 * `pi rad = `pi/4 rad.

To convert 60 degrees:

60 deg * (`pi rad / 180 deg) = ( 60 deg / ( 180 deg) ) * `pi rad = 1/3 * `pi rad = `pi/3 rad.

......!!!!!!!!...................................

RESPONSE -->

self critique assessment: 3

.................................................

......!!!!!!!!...................................

16:15:02

`q014. Convert 50 deg and 78 deg to radians.

......!!!!!!!!...................................

RESPONSE -->

50 deg * `pi rad/180 deg = 50 pi deg rad / 180 deg = .278 pi rad

78 deg * `pi rad/180 deg = 78 pi deg rad / 180 deg = .433 pi rad

confidence assessment: 2

.................................................

......!!!!!!!!...................................

16:15:46

50 deg * (`pi rad / 180 deg) = ( 50 deg / ( 180 deg) ) * `pi rad = 5/18 * `pi rad = (5 `pi/ 18) rad.

78 deg * (`pi rad / 180 deg) = ( 78 deg / ( 180 deg) ) * `pi rad = 78/180 * `pi rad = (13 `pi/ 30) rad.

......!!!!!!!!...................................

RESPONSE -->

I guess it is more accurate to use the LCD instead of dividing the fraction out.

self critique assessment: 2

.................................................

......!!!!!!!!...................................

16:19:14

`q015. Convert (14 `pi / 9) rad to degrees.

......!!!!!!!!...................................

RESPONSE -->

14 `pi/9 * 180 deg / `pi rad = 2520 `pi deg rad / 9 `pi rad = 280 deg

confidence assessment: 2

.................................................

......!!!!!!!!...................................

16:19:53

Since the angle is given radians, we need to multiply by deg / rad to get the angle in degrees.

(14 `pi / 9) rad * ( 180 deg / (`pi rad)) = ( 14 `pi / 9 ) * (180 / `pi ) deg = ( 14 * 180 / 9) * (`pi / `pi) deg = 14 * 20 deg = 280 deg.

......!!!!!!!!...................................

RESPONSE -->

self critique assessment: 3

.................................................

&#

Your work looks very good. Let me know if you have any questions. &#