#$&* course mth 163 6/29 10:30am 014. `query 14*********************************************
.............................................
Given Solution: `a** We can calculate the rates of change of a quadratic function based on a series of consecutive intervals of constant length. We find that these rates change from interval to interval, and always by the same amount. Since the rates of change always change by the same amount, they are changing at a constant rate. ** &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): ------------------------------------------------ Self-critique rating: ********************************************* Question: `qexplain how to get the first few members of a sequence from its recurrence relation YYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYYY Your solution: Example: if we know that a(0) = 1 Then a(1-1) = a(0) +1 = a(1) = 2 Then a(2-1) = a(1) +1 = a(2) = 3 confidence rating #$&*: 2 ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
.............................................
Given Solution: `a** We let n be the first integer for which the value a(n) is not given, and we substitute this integer into the recurrence relation to evaluate a(n) for this 'new' integer, using values of a(n) for previous integers. If this is not possible then we have not been given enough information to evaluate the sequence. We then substitute the next integer and use values of a(n) for previous integers. We continue this process as long as necessary to get the results we need. ** &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& Self-critique (if necessary): ------------------------------------------------ Self-critique rating: " Self-critique (if necessary): ------------------------------------------------ Self-critique rating: " Self-critique (if necessary): ------------------------------------------------ Self-critique rating: #*&!