phy 201
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A ball starts with velocity 0 and accelerates uniformly down a ramp of length 30 cm, covering the distance in 5 seconds.
• What is its average velocity?
answer/question/discussion: ->->->->->->->->->->->-> :
average velocity = final position-initial position/time elapsed
=30cm-0cm/5sec = 6 cm/sec
• If the acceleration of the ball is uniform then its average velocity is equal to the average of its initial and final velocities.
You know its average velocity, and you know the initial velocity is zero.
What therefore must be the final velocity?
answer/question/discussion: ->->->->->->->->->->->-> :
average velocity = final position-initial position/time elapsed
final position = average velocity * time elapsed + initial position.
=6cm/sec*5sec + 0 = 30 +0 = 30cm
this question asked for a final velocity; 30 cm is not a velocity but a position
• By how much did its velocity therefore change?
answer/question/discussion: ->->->->->->->->->->->-> :
30 cm/sec.
• At what average rate did its velocity change with respect to clock time?
answer/question/discussion: ->->->->->->->->->->->-> :
average velocity = change in velocity / time= 30/5 = 6cm/sec
&#These quantities have units, which must be specified with the quantities. &#
• What would a graph of its velocity vs. clock time look like? Give the best description you can.
answer/question/discussion: ->->->->->->->->->->->-> :
The graph of velocity vs. clock time would look like a straight increasing line whose slop would be equal to 6.
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20 minutes
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&#Please compare your solutions with the expanded discussion at the link
Solution
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