cq_1_051

phy 201

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A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.

• What will be its velocity after the 3 seconds has elapsed?

answer/question/discussion: ->->->->->->->->->->->-> :

initial velocity = 12cm/s

final velocity= ?

acceleration= 8 cm/s^2

initial time = 3sec

final time = 3sec

Initial and final clock times aren't the same; they differ by 3 sec.

Acceleration = final velocity – initial velocity / final time – initial time

Final velocity = Acceleration * change in time + initial velocity

= 8 cm/sec^2* 0sec +12cm/s = 12cm/sec

8 cm/s^2 would be multiplied by `dt; however `dt isn't 0.

• Assuming that acceleration is constant, what will be its average velocity during this interval?

answer/question/discussion: ->->->->->->->->->->->-> :

Average velocity = initial velocity +final velocity / 2 = 12cm/s +12cm/s / 2= 12cm/sec

• How far will it travel during this interval?

answer/question/discussion: ->->->->->->->->->->->-> :

displacement = velocity / time = 12cm/sec / 3sec = 4cm

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20 minute

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