phy 201
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A ball accelerates at 8 cm/s^2 for 3 seconds, starting with velocity 12 cm/s.
• What will be its velocity after the 3 seconds has elapsed?
answer/question/discussion: ->->->->->->->->->->->-> :
initial velocity = 12cm/s
final velocity= ?
acceleration= 8 cm/s^2
initial time = 3sec
final time = 3sec
Initial and final clock times aren't the same; they differ by 3 sec.
Acceleration = final velocity – initial velocity / final time – initial time
Final velocity = Acceleration * change in time + initial velocity
= 8 cm/sec^2* 0sec +12cm/s = 12cm/sec
8 cm/s^2 would be multiplied by `dt; however `dt isn't 0.
• Assuming that acceleration is constant, what will be its average velocity during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
Average velocity = initial velocity +final velocity / 2 = 12cm/s +12cm/s / 2= 12cm/sec
• How far will it travel during this interval?
answer/question/discussion: ->->->->->->->->->->->-> :
displacement = velocity / time = 12cm/sec / 3sec = 4cm
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20 minute
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You almost have it.
Please compare your solutions with the expanded discussion at the link
Solution
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