phy201
Your 'cq_1_07.1' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
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A ball falls freely from rest at a height of 2 meters. Observations indicate that the ball reaches the ground in .64 seconds.
Based on this information what is its acceleration?
answer/question/discussion: ->->->->->->->->->->->-> :
first we will find the velocity as following:
velocity = displacement/time = 2m/0.64sec=3.1250m/sec
This is average velocity, and you need to identify it as average velocity to avoid the error you make below.
now we will find the acceleraion:
acceleration = change in velocity/time
= final velocity- initial velocity / time = 3.1250 - 0 / 0.64sec = 4.8828m/s
you failed to distinguish between average velocity and final velocity, which results in an error (fortunately this error, while not always easy to avoid, is easy to correct).
Is this consistent with an observation which concludes that a ball dropped from a height of 5 meters reaches the ground in 1.05 seconds?
answer/question/discussion: ->->->->->->->->->->->-> :
velocity = displacement / time = 5m/1.05 = 4.7619 m/s
Are these observations consistent with the accepted value of the acceleration of gravity, which is 9.8 m / s^2?
answer/question/discussion: ->->->->->->->->->->->-> :
yes, these observations are consistent with the accepted value of the acceleration of gravity , which is 9.8 m/s^2.
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10 minute
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