phy 201
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An automobile rolls 10 meters down a constant incline with slope .05 in 8 seconds, starting from rest. The same automobile requires 5 seconds to roll the same distance down an incline with slope .10, again starting from rest.
At what average rate is the automobile's acceleration changing with respect to the slope of the incline?
answer/question/discussion: ->->->->->->->->->->->-> :
acceleration = final velocity - initial velocity / final time - initial time = 0.10 - 0.05 / 5sec- 8sec = -0.00166 m/s^2
0.10 and 0.05 are not velocities, they are the slopes of the inclines.
There are two trials, both from rest down an incline 10 meters long. For each trial you are given the time required for the ball to roll down the incline.
For the first trial, what is the acceleration?
For the second trial, what is the acceleration?
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20 minute
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Sir I don't understand the above question and I don't know exactly how to solve it. I read all the related topics of the above question from the book as well as form the note but still didn't get it. If you please solve this question that would be very helpfull. Thank you!
You can easily answer this once you understand the question. For you this is mostly just a question of understanding the statement.
See my notes and see if you can answer the question before you look at the link below.
Please compare your solutions with the expanded discussion at the link
Solution
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