Query 3

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course Mth 151

1/17 11

Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.003. `Query 3

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Question: `qQuery 2.3.15 This might differ from the problem as given in the text, but you should be able to answer it for the given sets: universal set U = {a,b, c,…,g}, X={a,c,e,g}, Y = {a,b,c}, Z = {b, ..., f}

What is the set (Y ^ Z')U X?

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Your solution: (Y ^ Z’) U X

({a, b, c} ^ {a, g}) U {a, c, e, g} First we have to work what is in parentheses. Z’ means everything that is in the universal set which is not in Z. In this case that is a & g. {a} U {a, c, e, g} Then we have to find the intersection of collections Y and Z’. That simply means the number that they have in common which is a.

{a} U {a, c, e, g}= {a, c, e, g} The union of the two sets equals {a, c, e, g}.

confidence rating #$&*: 3

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Given Solution:

`a**Z' = {a,g}, the set of all elements of the universal set not in Z. Y ^ Z' = {a}, since a is the only element common to both Y and Z'.

So (Y ^ Z') U X = {a, c, e, g}, the set of all elements which lie in at least one of the sets (Y ^ Z') U X. **

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Self-critique (if necessary): I think I did all the right stuff.

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Self-critique Rating: 3

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Question: `qGive the intersection of the two sets Y and Z'

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Your solution: Y = {a, b, c} Z’ = {a, g}

Y ^ Z’ = {a}

confidence rating #$&*: 3

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Given Solution:

`a**Z' = {a,g}, the set of all elements of the universal set not in Z. Y ^ Z' = {a}, since a is the only element common to both Y and Z'.**

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Self-critique (if necessary): Ha ha!! Got it right!

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Self-critique Rating: 3

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Question: `qQuery 2.3.32 (formerly 2.3.30). This was not assigned, but you answered a series of similar questions and should be able to give a reasonable answer to this one: Describe in words (A ^ B' ) U (B ^ A')

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Your solution: Ugh! Ummm…. The intersection of the elements of set A and all of the elements that are not in B joined to the intersection of B and all the elements that are not in A.

confidence rating #$&*: 2

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Given Solution:

`a** a description, not using a lot of set-theoretic terms, of (A ^ B' ) U (B ^ A') would be, all the elements that are in A and not in B, or that are not in A and are in B

Or you might want to say something like 'elements which are in A but not B OR which are in B but not A'.

STUDENT SOLUTION WITH INSTRUCTOR COMMENT:everything that is in set A and not in set B or everything that is in set B and is not in set A.

INSTRUCTOR COMMENT: I'd avoid the use of 'everything' unless the word is necessary to the description. Otherwise it's likely to be misleading. **

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Self-critique (if necessary): Okay, I think I get it.

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Self-critique Rating:1

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Question: `q2.3.53 (formerly 2.3.51) Is it always or not always true that n(A U B) = n(A)+n(B)? This was not among the assigned questions but having completed the assignment you should be able to answer this.

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Your solution: It is not always true because when A and B are joined, they may have some of the same elements and therefore bring the number of elements down. When you add the number of elements in A to the number of elements in B, there won’t be any duplications.

confidence rating #$&*: 3

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Given Solution:

`a** This conclusion is contradicted by many examples, including the one of the dark-haired and bright-eyed people in the q_a_.

Basically n(A U B) isn't equal to n(A) + n(B) if there are some elements which are in both sets--i.e., in the intersection.

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MORE DETAIL: The statement can be either true or false, depending on the sets A and B; it is not always true.

The statement n(A U B) = n(A)+n(B) means that the number of elements in A U B is equal to the sum of the number of elements in A and the number of elements in B.

The statement would be true for A = { c, f } and B = { a, g, h} because A U B would be { a, c, f, g, h} so n(A U B) = 5, and n(A) + n(B) = 2 + 3 = 5.

The statement would not be true for A = { c, f, g } and B = { a, g, h} because A U B would be the same as before so n(AUB) = 5, while n(A) + n(B) = 3 + 3 = 6.

The precise condition for which the statement is true is that A and B have nothing in common. In that case n(A U B) = n(A) + n(B). A more precise mathematical way to state this is to say that n(A U B) = n(A) + n(B) if and only if the intersection A ^ B of the two sets is empty. **

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Self-critique (if necessary):

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Self-critique Rating: 3

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Question: `qQuery 2.3.60 X = {1,3,5}, Y = {1,2,3}. Find (X ^ Y)' and X' U Y'.

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Your solution: First we must perform the problem in parentheses. (X^Y)’

( {1,3,5} ^ {1,2,3})’

Then we must find the intersection. ({1,3})’

Now we have to list all the elements outside of 1 and 3. {2, 5}

2 and 5 is our answer.

confidence rating #$&*: 3

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Given Solution:

`a** X ^ Y = {1,3} so (X ^ Y) ' = {1,3}' = {2, 4, 5}.

(X ' U Y ' ) = {2, 4} U {4, 5} = {2, 4, 5}

The two resulting sets are equal so a reasonable conjecture would be that (X ^ Y)' = X' U Y'. **

STUDENT QUESTION:

Where did the 4 come from?

INSTRUCTOR RESPONSE:

I believe this problem, as stated in the text, indicates that the universal set is {1, 2, 3, 4, 5}.

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Self-critique (if necessary): I repeat… Where did the 4 come from?! No, I understand. It makes sense.

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Self-critique Rating: 2

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Question: `q2.3.72 A = {3,6,9,12}, B = {6,8}.

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Your solution: A X B= {(3, 6) (3, 8) (6, 6) (6, 8) (9,6) (9, 8) (12, 6) (12, 8)}

B X A= {(6, 3) (6, 6) (6, 9) (6, 12) (8, 3) (8, 6) (8, 9) (8, 12)}

confidence rating #$&*: 3

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Given Solution:

`a** (A X B) = {(3,6),(3,8),(6,6),(6,8),(9,6),(9,8),(12,6), (12,8)}

(B X A) = (6,3),(6,6),(6,9),(6,12),(8,3),(8,6),(8,9),(8,12)}

How is n(A x B) related to n(A) and n(B)?

n(S) stands for the number of elements in the set S, i.e., its cardinality.

n(A x B) = n(A) * n(B) **

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Self-critique (if necessary):

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Self-critique Rating:3

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Question: `q2.3.84 Shade A U B

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Your solution: That means we will shade the overlapped section which includes both A and B.

confidence rating #$&*: 3

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Given Solution:

`a** everything in A and everything in B would be shaded. The rest of the universal set (the region outside A and B but still in the rectangle) wouldn't be. **

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Self-critique (if necessary): Whoops! I was thinking more along the lines of the intersection of A and B.

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Self-critique Rating: 0

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Question: `qQuery 2.3.100 Shade (A' ^ B) ^ C

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Your solution: First we have to figure out the part in parentheses. Everything that is not A in an intersection with B means that B is the answer in parentheses. Now we have B ^ C = …. This means that the overlap between B and C is shaded. No A overlaps are shaded. Only the overlap between B and C.

confidence rating #$&*: 3

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Given Solution:

`a** you would have to shade every region that lies outside of A and also inside B and also inside C. This would be the single region in the overlap of B and C but not including any part of A. Another way to put it: the region common to B and C, but not including any of A **

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Self-critique (if necessary): I got it!

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Self-critique Rating: 3

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Question: `qQuery 2.3.108. Describe the shading of the set (A ^ B)' U C.

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Your solution: Okay, the part in parentheses means that everything outside of the overlap between A and B is shaded. We add this to C. Now all elements outside of the overlap between A and B are shaded.

confidence rating #$&*: 2

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Given Solution:

`a** All of C would be shaded because we have a union with C, which will include all of C.

Every region outside A ^ B would also be shaded. A ^ B is the 'overlap' region where A and B meet, and only this 'overlap' would not be part of (A ^ B) '. The 'large' parts of A and B, as well as everything outside of A and B, would therefore be shaded.

Combining this with the shading of C the only the part of the diagram not shaded would be that part of the 'overlap' of A and B which is not part of C. **

STUDENT QUESTION

I think I understand because the ‘ was outside the ( ) then only the answer to A^B would be prime. And so my answer is

wrong to the extent that the larger regions of A &B would also be shaded, but had it been (AUB)’ no part of either A or B

would have been Shaded?

INSTRUCTOR RESPONSE

Exactly. Very good question, which you answered very well.

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Self-critique (if necessary): I could have been a little more descriptive when explaining my answer, but other than that I reckon it’s okay.

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Self-critique Rating: 3

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Question: `q2.3.114 Largest area of A shaded (sets A,B,C). Write a description using A, B, C, subset, union, intersection symbols, ', - for the shaded region.

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Your solution: ( B U C)’ ^ A

confidence rating #$&*: 3

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Given Solution:

`a** Student Answer and Instructor Response:

(B'^C')^A

Instructor Response:

Good. Another alternative would be A - (B U C ), and others are mentioned below.

COMMON ERROR: A ^ (B' U C')

INSTRUCTOR COMMENT: This is close but A ^ (B' U C') would contain all of B ^ C, including a part that's not shaded. A ^ (B U C)' would be one correct answer. **

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Self-critique (if necessary):

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Self-critique rating:

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Question: `q2.3.114 Largest area of A shaded (sets A,B,C). Write a description using A, B, C, subset, union, intersection symbols, ', - for the shaded region.

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Your solution: ( B U C)’ ^ A

confidence rating #$&*: 3

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Given Solution:

`a** Student Answer and Instructor Response:

(B'^C')^A

Instructor Response:

Good. Another alternative would be A - (B U C ), and others are mentioned below.

COMMON ERROR: A ^ (B' U C')

INSTRUCTOR COMMENT: This is close but A ^ (B' U C') would contain all of B ^ C, including a part that's not shaded. A ^ (B U C)' would be one correct answer. **

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Self-critique (if necessary):

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Self-critique rating:

#*&!

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Question: `q2.3.114 Largest area of A shaded (sets A,B,C). Write a description using A, B, C, subset, union, intersection symbols, ', - for the shaded region.

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Your solution: ( B U C)’ ^ A

confidence rating #$&*: 3

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Given Solution:

`a** Student Answer and Instructor Response:

(B'^C')^A

Instructor Response:

Good. Another alternative would be A - (B U C ), and others are mentioned below.

COMMON ERROR: A ^ (B' U C')

INSTRUCTOR COMMENT: This is close but A ^ (B' U C') would contain all of B ^ C, including a part that's not shaded. A ^ (B U C)' would be one correct answer. **

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Self-critique (if necessary):

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Self-critique rating:

#*&!#*&!

@&

Well done. Keep up the good work.

Note that I've just within the last few hours updated the Queries to match problem numbers in the text.

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