Query 22

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course Mth 151

3/24 11

If your solution to stated problem does not match the given solution, you should self-critique per instructions at

http://vhcc2.vhcc.edu/dsmith/geninfo/labrynth_created_fall_05/levl1_22/levl2_81/file3_259.htm

Your solution, attempt at solution. If you are unable to attempt a solution, give a phrase-by-phrase interpretation of the problem along with a statement of what you do or do not understand about it. This response should be given, based on the work you did in completing the assignment, before you look at the given solution.

022. `query 22

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Question: `q4.6.9 {-1,0,1} group on multiplication?

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Your solution:

* -1 0 1

-1 1 0 -1

0 0 0 0

1 -1 0 1

It is closed because all of the numbers are in the set.

It has the commutative property.

It is associative.

The identity is 1 because it doesn’t change the answer.

Zero doesn’t have an inverse to make it one so this set doesn’t have the inverse property.

It cannot be a group if one of the properties isn’t satisfied so this is not a group.

confidence rating #$&*: 3

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Given Solution:

`a** There are four criteria for the group: closure, identity, inverse property, and associativity.

The lack of any one of these properties means that the set and operation do not form a group.

The set is closed on multiplication.

The identity is the element that when multiplied by other elements does not change them. The identity for this operation is 1, since 1 * -1 = -1, 1 * 0 = 0 and 1 * 1 = 1.

Inverses are pairs of elements that give you 1 when you multiply them. For example -1 * -1 = 1 so -1 is its own inverse. 1 * 1 = 1 so 1 is also its own inverse. However, 0 does not have an inverse because there is nothing you can multiply by 0 to get 1.

Since there is an element without an inverse this is not a group. **

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Self-critique (if necessary):

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Self-critique Rating:3

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Question: `q4.6.25 verify (NT)R = N(TR)

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Your solution: (NT)R = N(TR)

V R = N P

M = M

True statement

confidence rating #$&*: 3

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Given Solution:

`a** From the table

(NT)R= V R = M

and

N(TR)= N P = M

This verifies the identity. **

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Self-critique (if necessary):

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Self-critique Rating: 3

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Question: `qquery 4.6.33 inverse of T

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Your solution: Since Q is the identity, we need to find the letter that makes T make Q. The answer is T.

T

confidence rating #$&*: 3

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Given Solution:

`a** T is its own inverse because T T gives you the identity **

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Self-critique (if necessary):

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Self-critique Rating: 3

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Question: `q4.6.42. Explain what property is gained when the system of integers is extended to the system of rational numbers.

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Your solution: I really have no idea.

confidence rating #$&*: 0

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Given Solution:

`a** The set of integers is a group on addition, with identity 0 and every number x having additive inverse -x.

It is not a group on multiplication. It contains the identity 1 but does not contain inverses, except for 1 itself. This is because, for example, there is no integer you can multiply by 2 to get the identity 1.

If we extend the integers to the rational numbers we do get the inverses. The inverse of 2 is 1/2 since x * 1/2 = 1, the identity. In general the multiplicative inverse of x is 1 / x.

However we still don't have a group on multiplication since 0 still doesn't have an inverse, 1 / 0 being undefined on the real numbers. **

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Self-critique (if necessary):

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Self-critique rating:

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Question: `q4.6.42. Explain what property is gained when the system of integers is extended to the system of rational numbers.

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Your solution: I really have no idea.

confidence rating #$&*: 0

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Given Solution:

`a** The set of integers is a group on addition, with identity 0 and every number x having additive inverse -x.

It is not a group on multiplication. It contains the identity 1 but does not contain inverses, except for 1 itself. This is because, for example, there is no integer you can multiply by 2 to get the identity 1.

If we extend the integers to the rational numbers we do get the inverses. The inverse of 2 is 1/2 since x * 1/2 = 1, the identity. In general the multiplicative inverse of x is 1 / x.

However we still don't have a group on multiplication since 0 still doesn't have an inverse, 1 / 0 being undefined on the real numbers. **

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&#This also requires a self-critique.

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Self-critique (if necessary):

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Self-critique rating:

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&#Your work looks good. See my notes. Let me know if you have any questions. &#