#$&*
PHY 202
Your 'flow experiment' report has been received. Scroll down through the document to see any comments I might have inserted, and my final comment at the end.
#$&* Your initial message (if any): **
The Flow Experiment was submitted 8 Jun 2011 around 11:15 PM.
#$&* Is flow rate increasing, decreasing, etc.? **
FLOW EXPERIMENT - Alternate Soft Drink Botte
The picture below shows a graduated cylinder containing water, with dark coloring (actually a soft drink). Water is flowing out of the cylinder through a short thin tube in the side of the cylinder. The dark stream is not obvious but it can be seen against the brick background.
You will use a similar graduated cylinder, which is included in your lab kit, in this experiment. If you do not yet have the kit, then you may substitute a soft-drink bottle. Click here for instructions for using the soft-drink bottle.
In this experiment we will observe how the depth of water changes with clock time.
In the three pictures below the stream is shown at approximately equal time intervals. The stream is most easily found by looking for a series of droplets, with the sidewalk as background.
Based on your knowledge of physics, answer the following, and do your best to justify your answers with physical reasoning and insight:
As water flows from the cylinder, would you expect the rate of flow to increase, decrease or remain the same as water flows from the cylinder?
Your answer (start in the next line):
#$&* I believe as water flows from a cylinder, the rate of flow will decrease over time as the water flows from the cylinder.
As water flows out of the cylinder, an imaginary buoy floating on the water surface in the cylinder would descend.
Would you expect the velocity of the water surface and hence of the buoy to increase, decrease or remain the same?
Your answer (start in the next line):
#$&* I believe the velocity of the water surface and hence of the buoy to increase.
How would the velocity of the water surface, the velocity of the exiting water, the diameter of the cylinder and the diameter of the hole be interrelated? More specifically how could you determine the velocity of the water surface from the values of the other quantities?
Your answer (start in the next line):
#$&* Depending on the type of quantities given, the velocity of the water surface can be determined from quantities such as the depth: feet, meters, kph, feet per sec, mph, meters per sec.
The water exiting the hole has been accelerated, since its exit velocity is clearly different than the velocity it had in the cylinder.
Explain how we know that a change in velocity implies the action of a force?
Your answer (start in the next line):
#$&* The change in velocity will imply the action of a force has taken place because the water exiting from the cylinder has accelerated.
What do you think is the nature of the force that accelerates the water from inside the cylinder to the outside of the outflow hole?
Your answer (start in the next line):
#$&* The pressure from the volume of water inside the cylinder.
From the pictures, answer the following and justify your answers, or explain in detail how you might answer the questions if the pictures were clearer:
Does the depth seem to be changing at a regular rate, at a faster and faster rate, or at a slower and slower rate?
Your answer (start in the next line):
#$&* The depth of the water is changing at a faster rate.
What do you think a graph of depth vs. time would look like?
Your answer (start in the next line):
#$&* The graph will have a line that will increase from left to right.
Does the horizontal distance (the distance to the right, ignoring the up and down distance) traveled by the stream increase or decrease as time goes on?
Your answer (start in the next line):
#$&* The horizontal distance, the distance to the right, traveled by the stream will increase as time goes by.
Does this distance change at an increasing, decreasing or steady rate?
Your answer (start in the next line):
#$&* The distance will change at a steady rate.
What do you think a graph of this horizontal distance vs. time would look like? Describe in the language of the Describing Graphs exercise.
Your answer (start in the next line):
#$&* The time will be the x-axis and the horizontal distance will be the y-axis. The graph will have a line representing the horizontal distance vs. time that will increase from the left to the right.
Soft-drink bottle alternative
For students who use the soft-drink bottle as an alternative to the graduated cylinder:
Use a bottle which has a uniform cylindrical section. Most bottles are tapered at the top and the bottom, with a uniform cylindrical section in between.
Remove the label so you can easily observe the water level in the cylindrical section.
If you have a drill and a small drill bit (between about 1/16 inch and 1/8 inch), drill a hole near the bottom of the cylindrical section. If not, use something sharp and try to create a hole about 1/8 inch on a side; it's generally not difficult to make a triangular hole using a sharp blade. You can practice on a spare bottle, or if you prefer near the very top of the cylindrical section.
Instead of the milliliter markings, use a ruler or a ruler copy (the latter is a printable copy of a number of rulers; you may cut out a section and tape it to your bottle, which gives you a convenient scale to use for the experiment).
If you use this alternative, you should include the shape and dimensions of the hole, as best you can determine them.
Setup of the experiment is easy. You will need to set it up near your computer, so you can use a timing program that runs on the computer. The cylinder will be set on the edge of a desk or tabletop, and you will need a container (e.g., a bucket or trash can) to catch the water that flows out of the cylinder. You might also want to use a couple of towels to prevent damage to furniture, because the cylinder will leak a little bit around the holes into which the tubes are inserted.
Run the experiment, and copy and paste the contents of the TIMER program below:
Your answer (start in the next line):
#$&*
1 0.911 0.911
2 7.588 6.677
3 14.584 6.996
4 21.356 6.772
Measure the large marks on the side of the cylinder, relative to the height of the outflow tube. Put the vertical distance from the center of the outflow tube to each large mark in the box below, from smallest to largest distance. Put one distance on each line.
Your answer (start in the next line):
#$&* 20 cm
10 cm
Now make a table of the position of the water surface vs. clock time. The water surface positions will be the positions of the large marks on the cylinder relative to the outflow position (i.e., the distances you measured in the preceding question) and the clock times will as specified above (the clock time at the first position will be 0). Enter 1 line for each event, and put clock time first, position second, with a comma between.
For example, if the first mark is 25.4 cm above the outflow position and the second is 22.1 cm above that position, and water reached the second mark 2.45 seconds after release, then the first two lines of your data table will be
0, 25.4
2.45, 22.1
If it took another 3.05 seconds to reach the third mark at 19.0 cm then the third line of your data table would be
5.50, 19.0
Note that it would NOT be 3.05, 19.0. 3.05 seconds is a time interval, not a clock time. Again, be sure that you understand that clock times represent the times that would show on a running clock.
The second column of your TIMER output gives clock times (though that clock probably doesnt read zero on your first click), the third column gives time intervals. The clock times requested here are those for a clock which starts at 0 at the instant the water begins to flow; this requires an easy and obvious modification of your TIMERs clock times.
For example if your TIMER reported clock times of 223, 225.45, 228.50 these would be converted to 0, 2.45 and 5.50 (just subtract the initial 223 from each), and these would be the times on a clock which reads 0 at the instant of the first event.
Do not make the common error of reporting the time intervals (third column of the TIMER output) as clock times. Time intervals are the intervals between clicks; these are not clock times.
Your answer (start in the next line):
#$&*
0 s, 20.0 cm
7.588 s, 15.0 cm
14.584 s, 10.0 cm
21.356 s, 5.0 cm
You data could be put into the following format:
clock time (in seconds, measured from first reading) Depth of water (in centimeters, measured from the hole)
0 14
10 10
20 7
etc. etc.
Your numbers will of course differ from those on the table.
The following questions were posed above. Do your data support or contradict the answers you gave above?
Is the depth changing at a regular rate, at a faster and faster rate, or at a slower and slower rate?
Your answer (start in the next line):
#$&* The rate apparently changed at a regular rate.
Sketch a graph of depth vs. clock time (remember that the convention is y vs. x; the quantity in front of the vs. goes on the vertical axis, the quantity after the vs. on the horizontal axis). You may if you wish print out and use the grid below.
Describe your graph in the language of the Describing Graphs exercise.
Your answer (start in the next line):
#$&* The time will be the x-axis and the depth will be the y-axis. The graph will have a line representing the depth vs. time that will decrease from the left to the right.
caution: Be sure you didnt make the common mistake of putting time intervals into the first column; you should put in clock times. If you made that error you still have time to correct it. If you arent sure you are welcome to submit your work to this point in order to verify that you really have clock times and not time intervals
Now analyze the motion of the water surface:
For each time interval, find the average velocity of the water surface.
Explain how you obtained your average velocities, and list them:
Your answer (start in the next line):
#$&*
The average velocity is determined by the formula: vAve = ds / dt.
vAve = 20.0 cm / 0 s = 0 cm/s
vAve = 15.0 cm / 7.588 s = 1.98 cm/s
v Ave =10.0 cm / 14.584 s = 0.69 cm/s
vAve = 5.0 cm / 21.356 s = 0.23 cm/s
Assume that this average velocity occurs at the midpoint of the corresponding time interval.
What are the clock times at the midpoints of your time intervals, and how did you obtain them? (Give one midpoint for each time interval; note that it is midpoint clock time that is being requested, not just half of the time interval. The midpoint clock time is what the clock would read halfway through the interval. Again be sure you havent confused clock times with time intervals. Do not make the common mistake of reporting half of the time interval, i.e., half the number in the third column of the TIMERs output):
Your answer (start in the next line):
#$&*
@& Average rate of change of position with respect to clock time is change in position / change in clock time, not position / clock time.
You'll need to correct this.*@
11.133 sec
Make a table of average velocity vs. clock time. The clock time on your table should be the midpoint clock time calculated above.
Give your table below, giving one average velocity and one clock time in each line. You will have a line for each time interval, with clock time first, followed by a comma, then the average velocity.
Your answer (start in the next line):
#$&*
clock time (in seconds) Average velocity (in cm/s)
0 s 0 cm/s
7.588 s 1.96 cm/s
11.133 s 0.90 cm/s
14.584 s 0.69 cm/s
21.356 s 0.23 cm/s
Sketch a graph of average velocity vs. clock time. Describe your graph, using the language of the Describing Graphs exercise.
Your answer (start in the next line):
#$&* The clocktime time will be the x-axis and the average velocity will be the y-axis. The graph will have a line representing the average velocity vs. clock time that will increase initially and decrease at a decreasing rate.
For each time interval of your average velocity vs. clock time table determine the average acceleration of the water surface. Explain how you obtained your acceleration values.
Your answer (start in the next line):
#$&* The average acceleration can be determined by using the formula aAve = dv / dt.
aAve = 0 cm/s / 0 s = 0 cm/s^2
aAve = 1.96 cm/s / 7.588 s = 0.26 cm/s^2
aAve = 0.90 cm/s / 11.133 s = 0.08 cm/s^2
aAve = 0.69 cm/s / 14.582 s = 0.05 cm/s^2
aAve = 0.23 cm/s / 21.356 s = 0.01 cm/s^2
Make a table of average acceleration vs. clock time, using the clock time at the midpoint of each time interval with the corresponding acceleration.
Give your table in the box below, giving on each line a midpoint clock time followed by a comma followed by acceleration.
Your answer (start in the next line):
#$&*
@& Your results do not follow from the definition of aveage rate of change. You have found v / t, not dv / dt.*@
clock time (in seconds) Average acceleration (in cm/s^2)
0 s 0 cm/s^2
7.588 s 0.26 cm/s^2
11.133 s 0.08 cm/s^2
14.584 s 0.05 cm/s^2
21.356 s 0.01 cm/s^2
Answer two questions below:
Do your data indicate that the acceleration of the water surface is constant, increasing or decreasing, or are your results inconclusive on this question?
Do you think the acceleration of the water surface is actually constant, increasing or decreasing?
Your answer (start in the next line):
#$&* The data above indicates that the acceleration of the water is decreasing.
I believe the acceleration of the water is actually decreasing.
Go back to your graph of average velocity vs. midpoint clock time. Fit the best straight line you can to your data.
What is the slope of your straight line, and what does this slope represent? Give the slope in the first line, your interpretation of the slope in the second.
How well do you think your straight line represents the actual behavior of the system? Answer this question and explain your answer.
Is your average velocity vs. midpoint clock time graph more consistent with constant, increasing or decreasing acceleration? Answer this question and explain your answer.
Your answer (start in the next line):
#$&* The slope can be determine by calculating the Rise over the Run: Slope = Rise/Run.
*#&!
@& Most of your results after my first note are based on erroneous calculations.
&#Please see my notes and, unless my notes indicate that revision is optional, submit a copy of this document with revisions and/or questions, and mark your insertions with &&&& (please mark each insertion at the beginning and at the end).
Be sure to include the entire document, including my notes.
If my notes indicate that revision is optional, use your own judgement as to whether a revision will benefit you. &#
*@