course Mth 163 ·|m±ÔË_ÉÒ¨ùŠú™Ë—þÙÕ³ÍÎ÷ÄŒªÜK{assignment #008 008. Precalculus I 02-17-2008
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16:10:19 `q001. Note that this assignment has 4 questions For the function y = 1.1 x + .8, what are the coordinates of the x = 2 and x = 9 points? What is the rise between these points and what is the run between these points? What therefore is the slope between these points?
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RESPONSE --> The coordinate for x = 2 is (2, 3) and the coordinate for x = 9 is (9, 10.7). The rise is 7.7 and the run is 7, thus 7.7/7 equals 1.1 which is the slope. confidence assessment: 3
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16:12:33 `q002. For the function y = 1.1 x + .8, what are the coordinates of the x = a point, in terms of the symbol a? What are the coordinates of the x = b point, in terms of the symbol b?
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RESPONSE --> The coordinate for x = a is (a, 1.1a + .8) and the coordinate for x = b is (b, 1.1b + .8). confidence assessment: 3
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16:14:56 `q003. We see that the coordinates of the x = a point are (a, 1.1 a + .8) and (b, 1.1 b + .8). What therefore is the rise between these two points? What is the run between these two points?
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RESPONSE --> The rise is (1.1b + .8) - (1.1a + .8) which equals 1.1b - 1.1a. The run is equal to a - b. confidence assessment: 3
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16:18:33 `q004. We see that the rise between the x = a and x = b points of the graph of y = 1.1x +.8 is 1.1 b + .8 - (1.1 a + .8), while the run is b - a. What therefore is the average slope of the graph between these points? Simplify your answer.
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RESPONSE --> The slope is equal to (1.1b - 1.1a) / b-a which is equal to +/- 1. confidence assessment: 1
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16:19:21 end program
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RESPONSE --> Understand. OK self critique assessment: 3
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